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3 years ago

Equation that would have infinitely many solutions with 5x+3y=12

1 answer:

6 0

10x+6y=24, 15x+9y=36. If you multiply both sides by a number (2,3 etc) you get an equation that would have infinitely many solutions because they’re the same equation. Hope this could help you!! Gamer time

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Solve the formula please!!!!!!!!

Rashid [163]

Answer:

Option A. is the right choice.

Step-by-step explanation:

$\frac{1}{3}b^2h=V\\\\hb^2=3V\\\\b^2=\frac{3V}{h}\\\\b=\sqrt{\frac{3V}{h}}$

Best Regards!

4 0

2 years ago

Read 2 more answers

Suppose that a car rental agency charges a fixed amount per day plus an amount per mile for renting a car. Heidi rented a car on

elena55 [62]

9514 1404 393

Answer:

f(x) = 0.15x +25

Step-by-step explanation:

We are given two points:

(x, y) = (180, 52) or (350, 77.50)

The slope is given by ...

m = (y2 -y1)/(x2 -x1)

m = (77.50 -52)/(350 -180) = 25.50/170 = 0.15

The y-intercept is given by ...

b = y -mx

b = 52 -0.15×180 = 25

Then the equation for the linear function is ...

f(x) = mx +b

f(x) = 0.15x +25

8 0

2 years ago

Which fraction can be expressed as a repeating decimal?<br> A; 1/10<br> B; 1/4<br> C; 3/5<br> D; 7/9

Tju [1.3M]

Answer: The answer is D

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Let T be the plane-2x-2y+z =-13. Find the shortest distance d from the point Po=(-5,-5,-3) to T, and the point Q in T that is cl

GaryK [48]

Answer:

d=10u

Q(5/3,5/3,-19/3)

Step-by-step explanation:

The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane $n=(-2,-2,1)$ , then r will have the next parametric equations:

$x=-5-2\lambda\\y=-5-2\lambda\\z=-3+\lambda$

To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T

$-2x-2y+z =-13\\-2(-5-2\lambda)-2(-5-2\lambda)+(-3+\lambda) =-13\\10+4\lambda+10+4\lambda-3+\lambda=-13\\9\lambda+17=-13\\9\lambda=-13-17\\\lambda=-30/9=-10/3$

Substitute the value of $\lambda$ in the parametric equations:

$x=-5-2(-10/3)=-5+20/3=5/3\\y=-5-2(-10/3)=5/3\\z=-3+(-10/3)=-19/3\\$

Those values are the coordinates of Q

Q(5/3,5/3,-19/3)

The distance from Po to the plane

$d=\left| {\to} \atop {PoQ}} \right|=\sqrt{(\frac{5}{3}-(-5))^2+(\frac{5}{3}-(-5))^2+(\frac{-19}{3}-(-3))^2} \\d=\sqrt{(\frac{5}{3}+5))^2+(\frac{5}{3}+5)^2+(\frac{-19}{3}+3)^2} \\d=\sqrt{(\frac{20}{3})^2+(\frac{20}{3})^2+(\frac{-10}{3})^2}\\d=\sqrt{\frac{400}{9}+\frac{400}{9}+\frac{100}{9}}\\d=\sqrt{\frac{900}{9}}=\sqrt{100}\\d=10u$

7 0

2 years ago

Find x, then find each angle.

SCORPION-xisa [38]

Answer:

send the pic...........

8 0

2 years ago