Ask question

Ask question

All categories

nikitadnepr [17]

2 years ago

8

Write the point-slope form of the equation of the line that passes through the points (-8, 2) and (1, -4). Include your work in

your final answer.

2 answers:

Tatiana [17]2 years ago

3 0

Slope = (2+4)(-8 -1) = 6/-9 = - 2/3

<span>point-slope form of the equation
</span>
y - 2 = -2/3(x + 8)

ipn [44]2 years ago

3 0

Here's my work
Hope this helps

You might be interested in

consider the function and then use calculus to answer the questions that follow 1 1/x 5/x^2 1/x^3 (a) Find the interval(s) where

boyakko [2]

Answer:

a) $X=((-15-\sqrt{201},(-15+\sqrt{201}),(0,\infty)$

b) $Y=(\infty,\frac{1}{2}(-15-\sqrt{201} ) ),(\frac{1}{2}()-15+\sqrt{201)},0 )$

Step-by-step explanation:

From the question we are told that

The Function

$f(x)=1+\frac{1}{x} +\frac{5}{x^2} +\frac{1}{x^3}$

Generally the differentiation of function f(x) is mathematically solved as

$f(x)=1+\frac{1}{x} +\frac{5}{x^2} +\frac{1}{x^3}$

$f(x)=\frac{x^3+x^2+5x+1}{x^2}$

Therefore

$f'(x)=\frac{x^2+10x+3}{x^4}$

Generally critical point is given as

$f'(x)=0$

$\frac{x^2+10x+3}{x^4}=0$

$x=-5 \pm\sqrt{22}$

Generally the maximum and minimum x value for critical point is mathematically solved as

$f'(-5 \pm\sqrt{22})$

Where

Maximum value of x

$f'(-5 +\sqrt{22})$

Minimum value of x

$f'(-5 +\sqrt{22})$

Therefore interval of increase is mathematically given by

$f'(-5 -\sqrt{22}),f'(-5 +\sqrt{22})$

$f(x)$

Therefore interval of decrease is mathematically given by

$(-\infty,-5 -\sqrt{22}),f'(-5 +\sqrt{22},0),(0,\infty)$

Generally the second differentiation of function f(x) is mathematically solved as

$f''(x)=\frac{2(x^2+15x+6)}{x^5}$

Generally the point of inflection is mathematically solved as

$f''(x)=0$

$x^2+15x+6=0$

Therefore inflection points is given as

$x=\frac{1}{2} (-15 \pm \sqrt{201}$

$f''(x)>0,\frac{1}{2}(-15-\sqrt{201})$

a)Generally the concave upward interval X is mathematically given as

$X=((-15-\sqrt{201},(-15+\sqrt{201}),(0,\infty)$

$f''(x)$

b)Generally the concave downward interval Y is mathematically given as

$Y=(\infty,\frac{1}{2}(-15-\sqrt{201} ) ),(\frac{1}{2}()-15+\sqrt{201)},0 )$

5 0

2 years ago

Find K' if the figure is reflected across the x-axis

snow_lady [41]

<h3>Answer: K ' is at (1, 4)</h3>

Explanation:

Point K is located at (1, -4)

We use the rule that $(x,y) \to (x,-y)$ when reflecting over the x axis.

The x coordinate stays the same, but the y coordinate flips from positive to negative or vice versa.

Therefore, K(1,-4) will move to K ' (1, 4)

5 0

2 years ago

Sam and bethan share £54 in the ration 5:4

Margarita [4]

Answer:

<h2>Let the common ratio b x thus the part becomes</h2><h2>=5x and 4x respectively</h2>

<h2>Thus,ATQ</h2>

<h2>5x+4x= 54</h2>

<h2>9x=54</h2>

<h2>x= 6</h2>

<h2>Sam will get is £30 (putting the value of x)</h2><h2>and Bethan will get £24</h2>

3 0

2 years ago

A trapezoid has an area of 266.4 square feet. One base is 8.5 feet long. The height measures 24 feet. What is the length of the

exis [7]

266.4 - 8.5 - 24 will give you the answer of 233.9

6 0

3 years ago

Does brainly customer support have a phone number it wont let me use my brainly plus on the same account on the computer this is

serious [3.7K]

Answer:nope

Step-by-step explanation: I wish

6 0

3 years ago