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2 years ago

6 * 10^8 is how many times as large as 2 * 10^3

Mathematics

2 answers:

REY [17]2 years ago

6 0

Answer:

300000 or 3 * 10^5

Maslowich2 years ago

5 0

Hope this helps good luck

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What is the solution of the equation? (√2x-1) + 2=x

Gwar [14]

Answer:

x = 5

Step-by-step explanation:

√(2x − 1) + 2 = x

√(2x − 1) = x − 2

2x − 1 = (x − 2)²

2x − 1 = x² − 4x + 4

0 = x² − 6x + 5

0 = (x − 1) (x − 5)

x = 1 or 5

Check for extraneous solutions.

√(2(1) − 1) + 2 = 1

√(1) + 2 = 1

3 = 1

No solution

√(2(5) − 1) + 2 = 5

√(9) + 2 = 5

5 = 5

x = 5

7 0

3 years ago

39,012 in expanded form

Helen [10]

30,000 + 9,000 + 10 + 2

6 0

3 years ago

These two rectangles are similar. Which is a correct proportion for corresponding sides?

Keith_Richards [23]

Answer:

option (2) is correct.

$\frac{4}{8}=\frac{12}{x}$

Step-by-step explanation:

Given two similar rectangles and with dimension of sides,

we have to choose the correct proportion for corresponding sides.

Since, the rectangles given are similar rectangles.

So, the corresponding sides are in same proportion in case of similar figures,

So,

$\frac{4}{8}=\frac{12}{x}$

Thus, option (2) is correct.

7 0

2 years ago

Read 2 more answers

A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 43 ft/s. Its height

Lina20 [59]

Answer:

Instantaneous Velocity at t = 1 is 20 feet per second

Step-by-step explanation:

We are given he following information in the question:

$y(t)=43t-23t^{2}$

B) Instantaneous Velocity at t = 1

$y(1) = 43(1)-23(1)^2 = 20$

A) Formula:

Average velocity =

$\displaystyle\frac{\text{Displacement}}{\text{Time}}$

1) 0.01

$y(1 + 0.01)=y(1.01) = 43(1.01)-23(1.01)^{2} = 19.9677\\\\\text{Average Velocity} = \dfrac{y(1.01)-y(1)}{1.01-1} =\dfrac{19.9677-20}{1.01-1}= \dfrac{-0.0323}{0.01} = -3.230000 \text{feet per second}$

2) 0.005 s

$y(1 + 0.005)=y(1.005) = 43(1.005)-23(1.005)^{2} = 19.984425\\\\\text{Average Velocity} = \dfrac{y(1.005)-y(1)}{1.005-1} =\dfrac{19.984425-20}{1.005-1} = -3.1150000 \text{feet per second}$

3) 0.002 s

$y(1 + 0.002)=y(1.002) = 43(1.002)-23(1.002)^{2} = 19.993908\\\\\text{Average Velocity} = \dfrac{y(1.002)-y(1)}{1.002-1} =\dfrac{19.993908-20}{1.002-1} = -3.0460000 \text{feet per second}$

4) 0.001 s

$y(1 + 0.001)=y(1.001) = 43(1.001)-23(1.001)^{2} = 19.996977\\\\\text{Average Velocity} = \dfrac{y(1.001)-y(1)}{1.001-1} =\frac{19.996977-20}{1.001-1} = -3.0230000 \text{feet per second}$

3 0

2 years ago

Convert to the given unit Quarts and cups

Gennadij [26K]

Answer: 20

Step-by-step explanation:

8 0

1 year ago