The question is asking what v_final is, given that v_initial is at 300 feet. and v_initial is at 0 feet.
We know there will be a constant downward acceleration of 32.15 ft/s^2.
Use the following equation:
v_final^2 = v_initial^2 + 2ah
v_final^2 = (160 ft/s)^2 + 2(-32.15 ft/s^2)(300 ft) = 6310 ft^2/s^2
v_final = (6310 ft^2/s^2)^1/2 = 79.4 ft/s.
Are you looking for the length from E to F?
I think it would be 36 it’s what my friend told me I’m not sure though sorry if it’s wrong.
Answer:
(3r+8)(4+1)
Step-by-step explanation:
Answer:
11/12, 5/7, 1,8, 1/4, 1/2
Step-by-step explanation:
