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svetoff [14.1K]
3 years ago
6

Name the postulate of the therom qts=srq

Mathematics
1 answer:
GalinKa [24]3 years ago
6 0

Answer:

Seeing that we have a shared hypotenuse and two sides that are congruent, the theorem that we can use is the HL Theorem.

Step-by-step explanation:

mark brainliest :)

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Sphinxa [80]

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Step-by-step explanation:

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Prove that csc x - cot x is the same as (sin x)/(1 + cos x)
Lera25 [3.4K]
\csc x-\cot x=\dfrac{\sin x}{1+\cos x}\\\\L_s=\dfrac{1}{\sin x}-\dfrac{\cos x}{\sin x}=\dfrac{1-\cos x}{\sin x}\\\\R_s=\dfrac{\sin x}{1+\cos x}\cdot\dfrac{1-\cos x}{1-\cos x}=\dfrac{\sin x(1-\cos x)}{1^2-\cos^2x} =\dfrac{\sin x(1-\cos x)}{1-\cos^2x}\\\\=\dfrac{\sin x(1-\cos x)}{\sin^2x}=\dfrac{1-\cos x}{\sin x}\\\\L_s=R_s

\text{Used:}\\\\\csc x=\dfrac{1}{\sin x}\\\\\cot x=\dfrac{\cos x}{\sin x}\\\\a^2-b^2=(a-b)(a+b)\\\\\sin^2x+\cos^2x=1\to\sin^2x=1-\cos^2x
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3 years ago
An airplane is ascending at a constant rate of 15 feet per second what is the change in altitude during 10 minutes of flight
fenix001 [56]

Answer:

9000 ft

Step-by-step explanation:

Given: A airplane is ascending at a constant rate of 15 feet per second,

What we need to know: The change in altitude during 10 minutes of flight,

60 seconds = 1 minute

60 × 10

= 600 seconds

600 × 15

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Therefore there was a 9000 ft change in altitude during the 10 minutes of the flight.

6 0
3 years ago
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