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3 years ago

How do you graph y=2x-10

1 answer:

6 0

One of the easier approaches would be that of x- and y-intercepts.

Setting x=0 results in y=-10; the y-intercept is (0, -10).
Setting y = 0 results in x = 5, so the x-intercept is (5,0).

Plot these 2 points. Then draw a str. line thru these points.

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Given the equation F=9/5C +32 where C is the temperature in degrees Celsius and F is the corresponding temperature in degrees Fa

pentagon [3]

Answer:

Step-by-step explanation:

7 0

2 years ago

20x^2-30=4x solve for x

ankoles [38]

Answer:

x=1.3288 or -1.1288

Step-by-step explanation:

Given $20x^{2}-30=4x$

Subtract 4x from both sides

$20x^{2}-4x-30=0$

Since we can factor out 2 from whole equation, let's factor out 2.

$2(10x^{2}-2x-15)=0$

Divide with 2 on both sides

$10x^{2}-2x-15=0$

We got the quadratic equation, we can solve for x using quadratic formula.

$x=\frac{-b\pm\sqrt{b^{2}-4ac} } {2a}$

$x=\frac{2\pm\sqrt{2^{2}-4X10X(-15)} } {2X10}$

$x=\frac{2\pm\sqrt{604} }{20}$

$x=\frac{2\pm2\sqrt{151}}{20}$

$x=1.3288or-1.1288$

8 0

2 years ago

Read 2 more answers

Somebody please help so I can pass, please

ASHA 777 [7]

First, we are going to find the vertex of our quadratic. Remember that to find the vertex $(h,k)$ of a quadratic equation of the form $y=a x^{2} +bx+c$ , we use the vertex formula $h= \frac{-b}{2a}$ , and then, we evaluate our equation at $h$ to find $k$ .

We now from our quadratic that $a=2$ and $b=-32$ , so lets use our formula:
$h= \frac{-b}{2a}$
$h= \frac{-(-32)}{2(2)}$
$h= \frac{32}{4}$
$h=8$
Now we can evaluate our quadratic at 8 to find $k$ :
$k=2(8)^2-32(8)+56$
$k=2(64)-256+56$
$k=128-200$
$k=-72$
So the vertex of our function is (8,-72)

Next, we are going to use the vertex to rewrite our quadratic equation:
$y=a(x-h)^2+k$
$y=2(x-8)^2+(-72)$
$y=2(x-8)^2-72$
The x-coordinate of the minimum will be the x-coordinate of the vertex; in other words: 8.

We can conclude that:
The rewritten equation is $y=2(x-8)^2-72$
The x-coordinate of the minimum is 8