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egoroff_w [7]
4 years ago
15

How do you graph y=2x-10

Mathematics
1 answer:
bixtya [17]4 years ago
6 0
One of the easier approaches would be that of x- and y-intercepts.

Setting x=0 results in y=-10; the y-intercept is (0, -10).
Setting y = 0 results in x = 5, so the x-intercept is (5,0).

Plot these 2 points.  Then draw a str. line thru these points.
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Determine the value of variables a, b, and c that make each equation true.
jeyben [28]

<u>Corrected Question </u>

Determine the values of a, b and c that make each equation true.

(x^a)^6=\dfrac{1}{x^{30}} \\\\(x^{-7})^{-4}=x^b\\\\(x^{-2})^c=x^{22}

Answer:

  • a=-5,
  • b=28
  • c=-11

Step-by-step explanation:

To solve for a,b and c, we apply the following laws of indices

\dfrac{1}{p^m}=p^{-m} \\\\(a^m)^n=a^{m X n}\\\\$If p^m=p^n,$ then m=n

Therefore :

<u> Part 1</u>

(x^a)^6=\dfrac{1}{x^{30}}\\\\x^{a*6}=x^{-30}\\6a=-30\\$Divide both sides by 6\\a=-5

<u>Part 2</u>

To solve for b

(x^{-7})^{-4}=x^b\\x^{-7*-4}=x^b\\x^{28}=x^b\\$Since they have the same base\\b=28

<u> Part 3</u>

To solve for c

(x^{-2})^c=x^{22}\\x^{-2*c}=x^{22}\\$Just as in part 2, the two sides of the equality have the same base, therefore:\\-2c=22\\Divide both sides by -2\\c=-11

3 0
4 years ago
A random sample of 49 statistics examinations was taken. the average score, in the sample, was 84 with a variance of 12.25. the
tester [92]

Since in this case we are only using the variance of the sample and not the variance of the real population, therefore we use the t statistic. The formula for the confidence interval is:

<span>CI = X ± t * s / sqrt(n)                      ---> 1</span>

Where,

X = the sample mean = 84

t = the t score which is obtained in the standard distribution tables at 95% confidence level

s = sample variance = 12.25

n = number of samples = 49

From the table at 95% confidence interval and degrees of freedom of 48 (DOF = n -1), the value of t is around:

t = 1.68

 

Therefore substituting the given values to equation 1:

CI = 84 ± 1.68 * 12.25 / sqrt(49)

CI = 84 ± 2.94

CI = 81.06, 86.94

 

<span>Therefore at 95% confidence level, the scores is from 81 to 87.</span>

6 0
4 years ago
Find the area of the triangle.
Anon25 [30]

Answer: 6

Step-by-step explanation:

\frac{b*h}{2}

b=4

h=3

12/2

6

5 0
3 years ago
PLEASE HELP WILL GIVE BRAINLIEST PLEASEEE
Iteru [2.4K]

Answer:

Gross monthly income:$1,125

Monthly Federal income tax (11.6%): $130.50

Monthly Social security (FICA) (6.2%): $69.75

Monthly Medicare (1.45%): $16.3125

Monthly State Tax (4%): $45

Monthly Local Tax (0.1%): $1.125

Total Monthly deductions $262.6875

Trey’s NMI $862.3125

Explanation:

Calculation for What is his monthly taxes

First step is to calculate the Gross monthly income

Using this formula

Gross monthly income=Annual salary/Numbers of months in a year

Let plug in the formula

Gross monthly income=$13,500/12 months

Gross monthly income=$1,125

Therefore the Gross monthly income is :$1,125

Monthly Federal income tax (11.6%): $130.50

($1,125*11.6%)

Monthly Social security (FICA) (6.2%): $69.75

($1,125*6.2%)

Monthly Medicare (1.45%): $16.3125

($1,125*1.45%)

Monthly State Tax (4%): $45

($1,125*4%)

Monthly Local Tax (0.1%): $1.125

($1,125*0.1%)

Total Monthly deductions $262.6875

($130.50+$69.75+$16.3125+$45+$1.125)

Trey’s NMI $862.3125

Trey’s NMI=Gross monthly income-Total Monthly deductions

Trey’s NMI=$1,125-$262.6875

Trey’s NMI=$862.3125

Therefore his monthly taxes are:

Gross monthly income:$1,125

Monthly Federal income tax (11.6%): $130.50

Monthly Social security (FICA) (6.2%): $69.75

Monthly Medicare (1.45%): $16.3125

Monthly State Tax (4%): $45

Monthly Local Tax (0.1%): $1.125

Total Monthly deductions $262.6875

Trey’s NMI $862.3125

Step-by-step explanation:

7 0
3 years ago
10[4 times 10 divided by9(6 two to the second power-4 to the second power)+1}
OLga [1]
<span>10(4*10÷(6²-4²)+1)
10(40÷(36+16)+1)
</span>10(40÷(52)+1)
10(40÷(52)+1)
10(0.7692307692+1)
10(1.7692307692)
17.692307692

You should probably round that:
17.69

8 0
3 years ago
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