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dlinn [17]
2 years ago
15

Apply the distributive property to create an equivalent expression. 4(x − 2 + y)

Mathematics
2 answers:
vitfil [10]2 years ago
5 0

Step-by-step explanation:

4x-8+4y

blah blah blah blah blah

Setler79 [48]2 years ago
5 0

Answer:

4x-8+4y

Step-by-step explanation:

Hope this is the correct answer.

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The value of x in x + 7 = 15 is_____​
madreJ [45]

Answer:

x=8

Step-by-step explanation:

x+7=15

 -7  -7

x=8

6 0
3 years ago
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A 12-foot ladder is placed against a vertical wall of a building, with the bottom of the ladder standing on the level ground 7 f
Airida [17]

Answer:

the ladder reaches up to 9.75 ft. high

Step-by-step explanation:

a^2+b^2=c^2

plug in the numbers

a^2+49=144

then subtract 49 from 144

a^2=95

then sq 95

a=9.75

3 0
3 years ago
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An outlier is a data value that is numerically distant from ________ of the other data points in a set of data
laila [671]

In the statement regarding outlier we have to fill "most" to complete the statement.

Given An outlier is a data value that is numerically distant from_________ of the other data points in a set of data.

We have to fill the blank. We can fill " most" in the blank.

If a number in data is more than 1.5 times the length of the box away from either of the upper and lower quartile of the distribution then that number is said to be an outlier.

There are two types of outliers: upper outliers, lower.

If any values in the data set are greater than the upper boundary then those values are the upper outliers.

If any values in the data set are less than the lower boundary then those values are called lower outliers.

Lower quartile =Q_{1}-1.5*IQR

Upper quartile=Q_{3}+1.5*IQR

Hence we have to use most in the sentence to complete it.

Learn more about outliers at brainly.com/question/3631910

#SPJ4

3 0
2 years ago
Three hundred three and two hundredths
inessss [21]

303.02

Three hundred three=303

Two hundredths= .02

= 303.02

3 0
3 years ago
Assume that T is a linear transformation. Find the standard matrix of T. T: R^3 right arrow R^2 , T(e 1) =(1,2), and T(e2 ) =( -
irina [24]

Answer:

A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]

Step-by-step explanation:

Given

T:R^3->R^2

T(e_1) = (1,2)

T(e_2) = (-4,6)

T(e_3) = (2,-6)

Required

Find the standard matrix

The standard matrix (A) is given by

Ax = T(x)

Where

T(x) = [T(e_1)\ T(e_2)\ T(e_3)]\left[\begin{array}{c}x_1&x_2&x_3\\-&&x_n\end{array}\right]

Ax = T(x) becomes

Ax = [T(e_1)\ T(e_2)\ T(e_3)]\left[\begin{array}{c}x_1&x_2&x_3\\-&&x_n\end{array}\right]

The x on both sides cancel out; and, we're left with:

A = [T(e_1)\ T(e_2)\ T(e_3)]

Recall that:

T(e_1) = (1,2)

T(e_2) = (-4,6)

T(e_3) = (2,-6)

In matrix:

(a,b) is represented as: \left[\begin{array}{c}a\\b\end{array}\right]

So:

T(e_1) = (1,2) = \left[\begin{array}{c}1\\2\end{array}\right]

T(e_2) = (-4,6)=\left[\begin{array}{c}-4\\6\end{array}\right]

T(e_3) = (2,-6)=\left[\begin{array}{c}2\\-6\end{array}\right]

Substitute the above expressions in A = [T(e_1)\ T(e_2)\ T(e_3)]

A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]

Hence, the standard of the matrix A is:

A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]

6 0
3 years ago
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