The correct question is
Ravi<span> is </span>driving 440 miles<span> to </span>visit his grandma<span>. if </span>he drives<span> at an average </span>rate<span> of 55 miles </span>per hour<span>, how </span>many hours will<span> it </span>take him<span> to </span>get<span> 3/4 of the </span>way there<span>?
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we have that
3/4 of the way--------------> (3/4)*440=330 miles
<span>I apply a rule of three
if 55 miles----------------> 1 hour
330 miles--------------> X
X=330/55=6 hour
the answer is 6 hour
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<span>There are several possible events that lead to the eighth mouse tested being the second mouse poisoned. There must be only a single mouse poisoned before the eighth is tested, but this first poisoning could occur with the first, second, third, fourth, fifth, sixth, or seventh mouse. Thus there are seven events that describe the scenario we are concerned with. With each event, we want two particular mice to become diseased (1/6 chance) and the remaining six mice to remain undiseased (5/6 chance). Thus, for each of the seven events, the probability of this event occurring among all events is (1/6)^2(5/6)^6. Since there are seven of these events which are mutually exclusive, we sum the probabilities: our desired probability is 7(1/6)^2(5/6)^6 = (7*5^6)/(6^8).</span>
36/35 or 1 1/35. Change the denominators to a common one of 35, which in order to get an equivalent fraction, you change it to 21/35 and 15/35.
Answer:
11
Step-by-step explanation:
If you add 11 6 times, you will get 66 or if you multiply 11 times 66 you will get 66.
