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2 years ago

A parking lot is 272.5 feet long and 151.25 feet wide. How much longer is the lot than it is wide?

Mathematics

2 answers:

Sergio [31]2 years ago

7 0

Answer: The correct option is (A) 121.25 feet.

Step-by-step explanation: Given that a parking lot is 272.5 feet long and 151.25 feet wide.

We are to find how much longer is the lot than it is wide.

Let, 'l' and 'w' be the length and width of the parking lot.

Then, l = 272.5 feet and w = 151.25 feet.

We have,

$l-w=272.5-151.25=121.25.$

Therefore, the length is 121.25 feet longer than the width.

Thus, (A) is the correct option.

Leona [35]2 years ago

6 0

121.25, the answer is A

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2 years ago

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=======================================================

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2 years ago

Please solution and answer a and b thanks you

Igoryamba

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A) 2280 and length is 12mm and width is 190mm

B) 190, 12

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3 years ago

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3 years ago

Read 2 more answers

A(n - 3) +8= bn for n please help me

Papessa [141]

Given equation: A(n - 3) +8= bn.

Solution: On the left side of the equation we have A(n-3).

We don't have any sign in between A and parenthesis (n-3).

So, we need to multiply A and (n-3).

We need to apply distributive property to multiply A and (n-3).

Distributing A over (n-3), we get

A(n-3) = A*n - 3*A = An -3A.

Substituting this value in original equation,

An -3A +8= bn.

We need to solve it for n, so we get n terms on a side.

We have An on left side, we need to get rid n from left side.

Subtracting An from both sides, we get

An -3A +8-An= bn-An.

-3A +8 = bn - An.

We can see n is a common factor on rigth side in bn-an.

Factoring out n on right side from bn-an.

-3A +8 = (b - A)n.

Dividing both sides by (b-A),

$\frac{(-3A+8)}{(b-A)} = \frac{(b-A)n}{(b-A)}$

On right (b-A) paranthiss cancelled and we get n on right side.

$\frac{(-3A+8)}{(b-A)} =n$ Final answer.

So, that would be our final answer

n = (-3A+8)/(b-A)

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3 years ago