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VMariaS [17]
2 years ago
14

A parking lot is 272.5 feet long and 151.25 feet wide. How much longer is the lot than it is wide?

Mathematics
2 answers:
Sergio [31]2 years ago
7 0

Answer: The correct option is (A) 121.25 feet.

Step-by-step explanation:  Given that a parking lot is 272.5 feet long and 151.25 feet wide.

We are to find how much longer is the lot than it is wide.

Let, 'l' and 'w' be the length and width of the parking lot.

Then, l = 272.5 feet   and    w = 151.25 feet.

We have,

l-w=272.5-151.25=121.25.

Therefore, the length is 121.25 feet longer than the width.  

Thus, (A) is the correct option.

Leona [35]2 years ago
6 0
121.25, the answer is A
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The number of wrecks at a certain intersection varies directly as the number of cars that travel through the intersection. If th
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Answer:

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Step-by-step explanation:

<u>Step 1: Identify</u>

<em>a</em> = x + 3

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<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Substitute [PT]:                                                                                                (x + 3)² + x² = (√117)²
  2. Expand [FOIL]:                                                                                                 x² + 6x + 9 + x² = (√117)²
  3. Combine like terms:                                                                                       2x² + 6x + 9 = (√117)²
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  5. [SPE] Subtract 117 on both sides:                                                                    2x² + 6x - 108 = 0
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Since we are dealing with positive values, we can disregard the negative root.

∴ x = 6

4 0
3 years ago
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