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VMariaS [17]
3 years ago
14

A parking lot is 272.5 feet long and 151.25 feet wide. How much longer is the lot than it is wide?

Mathematics
2 answers:
Sergio [31]3 years ago
7 0

Answer: The correct option is (A) 121.25 feet.

Step-by-step explanation:  Given that a parking lot is 272.5 feet long and 151.25 feet wide.

We are to find how much longer is the lot than it is wide.

Let, 'l' and 'w' be the length and width of the parking lot.

Then, l = 272.5 feet   and    w = 151.25 feet.

We have,

l-w=272.5-151.25=121.25.

Therefore, the length is 121.25 feet longer than the width.  

Thus, (A) is the correct option.

Leona [35]3 years ago
6 0
121.25, the answer is A
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marshall27 [118]

Answer:

The last answer

Step-by-step explanation:

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3 0
3 years ago
The ballpark made a total of $15,000 from ticket sales at Wednesday's game. The ballpark charges $20 for each adult ticket and $
kvasek [131]
Assume that the number of adult tickets is a and the number of child tickets is c.

We are given that the adult ticket is sold for 20$, the child ticket is sold for 10$ and that the total is $15,000. This means that:
20a + 10c = 15,000 ..........> equation I

We are also given that number of child tickets is 3 times that of adult's. This means that:
c = 3a .........> equation II

Substitute with equation II in equation I to get a as follows:
20a + 10c = 15,000
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c = 3a
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3 years ago
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Leokris [45]

Given:

The data values are

11, 12, 10, 7, 9, 18

To find:

The median, lowest value, greatest value, lower quartile, upper quartile, interquartile range.

Solution:

We have,

11, 12, 10, 7, 9, 18

Arrange the data values in ascending order.

7, 9, 10, 11, 12, 18

Divide the data in two equal parts.

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Divide each parenthesis in 2 equal parts.

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Now,

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Greatest value = 18

Lower quartile = 9

Upper quartile = 12

Interquartile range (IQR) = Upper quartile - Lower quartile

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Therefore, median is 10.5, lowest value is 7, greatest value is 18, lower quartile 9, upper quartile 12 and interquartile range is 3.

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3 years ago
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vovikov84 [41]
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3 years ago
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trasher [3.6K]

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Step-by-step explanation:

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