Answer:
-17
Step-by-step explanation:
-16r=272
16r=-272
r=-17
Answer:
Step-by-step explanation:
Given that
Group Group One Group Two
Mean 26.00 23.00
SD 2.00 4.00
SEM 0.40 1.21
N 25 11
where group I represents female servers and group II male servers.
We have to calculate confidence interval for 90% for difference in means
The mean of Group One minus Group Two equals 3.00
df = 34
standard error of difference = 0.993
t critical = 2.034 for 90% df 34
Hence confid. interval at 90%
=Mean diff ±2.034 * std error of diff
= (0.98, 5.02)
Answer:
52488y²
Step-by-step explanation:
first solve for 3³. then solve for 18²
3³=27
18²=324
27*324=8748
then multiply 8748 by 6y²
=52488y^2
Step-by-step explanation:
can you give me solution
