Answer:
Relative frequency of male nonparticipation is O.42
Step-by-step explanation:
Figure 1 is your partially filled frequency table.
1. Complete the table
(a) Total No
Total Yes + Total No = Total
102 + Total No = 187
Total No = 187 - 102
= 85
(b) Female No
Male No + Female No = Total No
40 + Female No = 85
Female No = 85 - 40
= 45
(c) Female Yes
Female Yes + Female No = Female Total
Female Yes + 45 = 95
Female Yes = 95 - 45
= 50
(d) Male Yes
Male Yes + Female Yes = Total Yes
Male Yes + 50 = 102
Male Yes = 102 - 50
= 52
(e) Male Total
Male Yes + Male No = Male Total
52 + 40 = Male Total
Male Total = 92
Figure 2 shows the completed table.
2. Frequency of Male No
There are 92 males, of whom 40 do not participate in an after-school activity.
The relative frequency of male nonparticipation is
40/92 = 0.43
Answer:
y= 0 x=1
Step-by-step explanation:
There would be 3 triangles formed.
Each interior angle of a triangle will sum up to 180 degrees.
The 1st triangle will have 130,25, and 25 as its angle measures.
The angle 130 degrees will be divided into 2 to create 2 right triangle. Each triangle will have angle measurements of 25, 65, and 90 degrees.
Answer:
Step-by-step explanation:
Isolate the term of x and y from one side of the equation.
<h3>y=-15x-5 and 11x+y=-17</h3>
First, you have to substitute.
Then, you solve.
Add by 5 from both sides.
-4x-5+5=-17+5
Solve.
-17+5=-12
-4x=-12
Divide by -4 from both sides.
-4x/-4=-12/-4
Solve.
-12/-4=3
<u>x=3</u>
y=-15*3-5
Solve.
PEMDAS stands for:
- Parenthesis
- Exponents
- Multiply
- Divide
- Add
- Subtract
15*3=45
Rewrite the problem down.
y=-45-5
Solve.
<u>y=-50</u>
<u>Therefore, the correct answer is y=-50 and x=3.</u>
I hope this helps you! Let me know if my answer is wrong or not.
X = 0, y = 4, z = -3
You can solve this by using the two equations with the z to create a fourth equation. Get the z's to equal each other my multiplying the whole equation by factors that would do so. Then subtract them from each other to get it to cancel out. Then you can use that equation along with the middle equation to solve for either x or y in the same way. Once you have one answer, you can use the middle equation to find the second one and any equation to find z.
