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maks197457 [2]
3 years ago
10

Which Expression is equivalent to the expression (3^2)^3?

Mathematics
1 answer:
Vaselesa [24]3 years ago
3 0
(3^2)^3=3^6

(3^2)^3=729

3^6=729
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The perimeter of the patio is 64 feet. The width of the patio is (x+2) feet and the length of the patio is (x+6) feet. What are
ValentinkaMS [17]

The formula for the perimeter is P = 2<em>w</em> + 2<em>l</em>, where <em>w</em> is the width and <em>l</em> is the length. It is given that the width = (x+2) and the length = (x+6). Therefore, we can make this equation:

P = 2<em>w</em> + 2<em>l</em>

64 = 2(x+2) + 2(x+6) ⇒ Distributive property

⇒ 64 = 2x + 4 + 2x + 12 ⇒ Combine like terms

⇒ 64 = 4x + 16 ⇒ Subtract 16 from both sides

⇒ 48 = 4x ⇒ Divide both sides by 4

⇒ x = 12

Then, we use x = 12 and substitute it in to find the length and width

<em>Width</em> = (x+2) = (12+2) = 14

<em>Length</em> = (x+6) = (12+6) = 18

The dimensions of the patio is <u>14 by 18</u>

5 0
3 years ago
This is algebra 1 math problem <br>f (×)=2/5x+10
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To find the inverse, interchange the variables and solve for y.

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3 years ago
What is 4(x−2)=3(2y−1) in standard form?
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8 0
3 years ago
What is 9 times 2.75
goldfiish [28.3K]
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The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp
yKpoI14uk [10]

Answer:

Confidence Interval in 95% confidence level for the quality rating is (6.06,7.46)

Step-by-step explanation:

Confidence Interval can be calculated using the formula M±ME where

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  • ME is the margin of error in a given confidence level

Using the sample obtained from 50 business travelers we get

  • Mean of the sample is 6.76
  • standard deviation of the sample is 2.526

Margin of error (ME) around the mean using the formula

ME=\frac{z*s}{\sqrt{N} } where

  • z is the corresponding statistic in 95% confidence level (1.96)
  • s is the standard deviation of the sample (2.526)
  • N is the sample size (50)

Using the numbers in the formula we get:

ME=\frac{1.96*2.526}{\sqrt{50} } ≈ 0.70

Then the confidence interval becomes 6.76±0.70

6 0
3 years ago
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