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german
4 years ago
6

Which of the questions are correct

Mathematics
1 answer:
Archy [21]4 years ago
4 0

The first, third and last are correct.

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The graph of y = f(x) is shown. Choose all the true statements.
dexar [7]

Answer:

−2 is a member of the domain of f.

f(0) > 0

Step-by-step explanation:

Statement 1 is TRUE. Domain value includes set of values of x of the function. -2 is plotted on the x-axis on the graph. Therefore, it is a member of domain of f.

Statement 2 is incorrect. Range includes all possible y-values of the function. On the graph, no y-value plotted is -2. Therefore, -2 is NOT a member of the range of f.

Statement 3 is TRUE.

f(0) is approximately 2.2 on the graph. i.e. at x = 0, y ≈ 2.2.

Therefore, f(0) > 0.

Statement 4 is INCORRECT.

f(2) = 1, that is at x = 2, y = 1 as seen in the graph. Therefore, f(2) is not greater than 2.

8 0
4 years ago
Help with #2 it has to do with number 1 that is the polygon you need to find the area of it.
Katena32 [7]
Okay, it's the equation to how find area any other way. A=L×W

This means *picture above*

So then you count over each line meaning 1.
This means L=9 and a 1/2. Since its in between the 2 an 3 on the x-axis.
Now for W or width. It equals 3 since you can count 2 lines and one either ends of the polygon is 1/2 each this creates one when added together.

All you do from there is multiply 9 and 3. This should give you A=area.

8 0
3 years ago
THIS IS URGENT! PLZ HELP!
Yanka [14]

Answer:

73

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
solve the system of linear equations using substitution. Which expression would be eastier to substitute into the other equation
Colt1911 [192]
The x=7y-4 one and put it to where the x in the other equation is.
7 0
4 years ago
A composition of a reflection and a translation is called a __________________
ivolga24 [154]
A reflection is a transformation across a line called the line of reflection, so that the line of reflection is the perpendicular bisector of each segment joining each point and its image. ... A translation is an isometry , so the image of a translated figure is congruent to the preimage.
8 0
3 years ago
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