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3 years ago

Is the graph of a function rule that relates a squares area to its side length continuous or discrete? Explain

Mathematics

1 answer:

ira [324]3 years ago

4 0

<span>the graph of a function rule that relates a squares area to its side length is continuous</span>

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Blake rows his boat against a current 90 yards in 15 minutes. With a current, he rows 90 yards in 9 minutes. What is the rate at

Anna71 [15]

Answer:

90 yards in 15 minutes =6 yds/min

90 yards in 9 minutes =10 yds/min

x = current rate

r = rowing rate

r + x = 10

r - x = 6 Adding both equations

2 r = 16

rowing rate = 8 yds/min

x = 2 yds/min (current rate)

Step-by-step explanation:

4 0

3 years ago

Martha is starting to save for a new laptop. She has been keeping track of her savings every day. The graph shows the number of

sammy [17]

Answer:

tell martha to buy huwei matebook x 2020 , its a good one

Step-by-step explanation:

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3 years ago

A golfball is hit from the ground with an initial velocity of 200 ft/sec. The horizontal distance that the golfball will travel,

algol13

Answer:

The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

Step-by-step explanation:

The formula from the maximum distance of a projectile with initial height h=0, is:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}$

Where $v_i$ is the initial velocity.

In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is $[0, \pi/2]$ . The critical points of the function are those who make $d'(\theta)=0$ :

$d(\theta)=\frac{v_i^2\sin(2\theta)}{g}\\d'(\theta)=\frac{v_i^2\cos(2\theta)}{g}*(2)\\d'(\theta)=\frac{2v_i^2\cos(2\theta)}{g}$

$d'(\theta)=0\\\frac{2v_i^2\cos(2\theta)}{g}=0\\\cos(2\theta)=0\\2\theta=\pi/2,3\pi/2,5\pi/2,...\\\theta=\pi/4,3\pi/4,5\pi/4,...$

The critical value inside the interval is $\pi/4$ .

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\d(\pi/4)=\frac{v_i^2sin(2(\pi/4))}{g}\\d(\pi/4)=\frac{v_i^2sin(\pi/2)}{g}\\d(\pi/4)=\frac{v_i^2(1)}{g}\\d(\pi/4)=\frac{(200)^2}{32}\\d(\pi/4)=\frac{40000}{32}\\d(\pi/4)=1250ft$

The second step is to find the values of the function at the endpoints of the interval:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\\theta=0\\d(0)=\frac{v_i^2sin(2(0))}{g}\\d(0)=\frac{v_i^2(0)}{g}=0ft\\\theta=\pi/2\\d(\pi/2)=\frac{v_i^2sin(2(\pi/2))}{g}\\d(\pi/2)=\frac{v_i^2sin(\pi)}{g}\\d(\pi/2)=\frac{v_i^2(0)}{g}=0ft$

The biggest value of f is gived by $\pi/4$ , therefore $\pi/4$ is the absolute maximum.

In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

4 0

3 years ago

Alex bikes 2 3/4 miles. Then, she runs 1 2/4 miles. The distance she bikes is how many times the distance she runs?

anastassius [24]

Answer:

The distance she bikes is 11/6 times as much as the distance she runs.

Step-by-step explanation:

Alex bikes 2.75 miles, runs 1.5 miles. The distance she bikes is 2.75/1.5 times as much as the distance she runs.

The distance she bikes is 11/6 times as much as the distance she runs.

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3 years ago

Read 2 more answers

people with severe hearing loss given a sentence and word recognition test six months after they got implants in their ears the

kirza4 [7]

That would be .82 as 82% is 82/100 so that makes the answer .82

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2 years ago