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AleksAgata [21]
3 years ago
6

the value of y varies directly proportional to the value of x. When x = 50, the value of y= 2500. What is the value of y, when x

= 96?

Mathematics
1 answer:
USPshnik [31]3 years ago
4 0

Answer:

The required value of y is 4800

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27.78585

Step-by-step explanation:

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Abby has a credit card which uses the adjusted balance method to compute finance charges. Her card has an APR of 11.83%, and she
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Read 2 more answers
1) 26 = 8 + v 2) 3 + p = 8
aleksklad [387]

Answer:

268+v2)3+p=8     =p=−3v2−796

Step-by-step explanation:

Let's solve for p.

(268+v2)(3)+p=8

Step 1: Add -804 to both sides.

3v2+p+804+−804=8+−804

3v2+p=−796

Step 2: Add -3v^2 to both sides.

3v2+p+−3v2=−796+−3v2

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<em><u>Hope this helps.</u></em>

5 0
3 years ago
Write 81.9 as a mixed number.
Digiron [165]

Answer:

81 9/10

Step-by-step explanation:

6 0
2 years ago
Which of the following geometric series converges?
Artist 52 [7]

All three series converge, so the answer is D.

The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.

Consider a geometric sequence with the first term <em>a</em> and common ratio |<em>r</em>| < 1. Then the <em>n</em>-th partial sum (the sum of the first <em>n</em> terms) of the sequence is

S_n=a+ar+ar^2+\cdots+ar^{n-2}+ar^{n-1}

Multiply both sides by <em>r</em> :

rS_n=ar+ar^2+ar^3+\cdots+ar^{n-1}+ar^n

Subtract the latter sum from the first, which eliminates all but the first and last terms:

S_n-rS_n=a-ar^n

Solve for S_n:

(1-r)S_n=a(1-r^n)\implies S_n=\dfrac a{1-r}-\dfrac{ar^n}{1-r}

Then as gets arbitrarily large, the term r^n will converge to 0, leaving us with

S=\displaystyle\lim_{n\to\infty}S_n=\frac a{1-r}

So the given series converge to

(I) -243/(1 + 1/9) = -2187/10

(II) -1.1/(1 + 1/10) = -1

(III) 27/(1 + 1/3) = 18

8 0
2 years ago
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