Answer:
27.78585
Step-by-step explanation:
Answer:
268+v2)3+p=8 =p=−3v2−796
Step-by-step explanation:
Let's solve for p.
(268+v2)(3)+p=8
Step 1: Add -804 to both sides.
3v2+p+804+−804=8+−804
3v2+p=−796
Step 2: Add -3v^2 to both sides.
3v2+p+−3v2=−796+−3v2
p=−3v2−796
<em><u>Hope this helps.</u></em>
Answer:
81 9/10
Step-by-step explanation:
All three series converge, so the answer is D.
The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.
Consider a geometric sequence with the first term <em>a</em> and common ratio |<em>r</em>| < 1. Then the <em>n</em>-th partial sum (the sum of the first <em>n</em> terms) of the sequence is

Multiply both sides by <em>r</em> :

Subtract the latter sum from the first, which eliminates all but the first and last terms:

Solve for
:

Then as gets arbitrarily large, the term
will converge to 0, leaving us with

So the given series converge to
(I) -243/(1 + 1/9) = -2187/10
(II) -1.1/(1 + 1/10) = -1
(III) 27/(1 + 1/3) = 18