![\huge\text{$x=\boxed{\sqrt{33}+4,\ -\sqrt{33}+4}$}](https://tex.z-dn.net/?f=%5Chuge%5Ctext%7B%24x%3D%5Cboxed%7B%5Csqrt%7B33%7D%2B4%2C%5C%20-%5Csqrt%7B33%7D%2B4%7D%24%7D)
To solve for
, we need to isolate it on one side of the equation.
Take the square root of both sides, making sure to use both positive and negative roots.
![\begin{aligned}(x-4)^2&=33\\x-4&=\pm\sqrt{33}\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%28x-4%29%5E2%26%3D33%5C%5Cx-4%26%3D%5Cpm%5Csqrt%7B33%7D%5Cend%7Baligned%7D)
cannot be simplified, so we'll leave it as-is.
Add
to both sides to fully isolate
.
![x=\pm\sqrt{33}+4](https://tex.z-dn.net/?f=x%3D%5Cpm%5Csqrt%7B33%7D%2B4)
Expand the solution by making two solutions, one where
is positive and one where it's negative.
![x=\sqrt{33}+4,\ x=-\sqrt{33}+4\\x=\boxed{\sqrt{33}+4,\ -\sqrt{33}+4}](https://tex.z-dn.net/?f=x%3D%5Csqrt%7B33%7D%2B4%2C%5C%20x%3D-%5Csqrt%7B33%7D%2B4%5C%5Cx%3D%5Cboxed%7B%5Csqrt%7B33%7D%2B4%2C%5C%20-%5Csqrt%7B33%7D%2B4%7D)
Answer:
9=x
Step-by-step explanation:
Answer:
Step-by-step explanation:
These come directly from my textbook, so I'm not sure if your teacher will accept this kind of work.
1. Angle construction:
Given an angle. construct an angle congruent to the given angle.
Given: Angle ABC
Construct: An angle congruent to angle ABC
Procedure:
1. Draw a ray. Label it ray RY.
2. Using B as center and any radius, draw an arc that intersects ray BA and ray BC. Label the points of intersection D and E, respectively.
3. Using R as center and the same radius as in Step 2, draw an arc intersecting ray RY. Label the arc XS, with S being the point where the arc intersects ray RY.
4. Using S as center and a radius equal to DE, draw an arc that intersects arc XS at a point Q.
5. Draw ray RQ.
Justification (for congruence): If you draw line segment DE and line segment QS, triangle DBE is congruent to triangle QRS (SSS postulate) Then angle QRS is congruent to angle ABC.
You can probably also Google videos if it's hard to imagine this. Sorry, construction is super hard to describe.
Answer: Due to its anonymous nature, if you lose your cash, it's gone. Payment cards can be cancelled and replaced swiftly and remotely. Whilst cash may offer you complete anonymity from data thieves, EMV chip enabled cards offer a more thorough form of payment authentication, providing an extra layer of payment security
So, therefore, C.
ANSWER: the man bought 5 shirts