Filling in one equation into the other will lead to elimination of one variable, enabling you to solve the other. In this case it is very easy to eliminate variable e right away. So you end up equating the terms of A and B:
4f + 1 = e = 3f+ 5
Forget e and you see it is answer D.
The answer is
q=3
-(3+14)=-3+-14
3+14=17--> -17
Answer:
Step-by-step explanation:
From the problem statement, each box of candles has the following range of candles:
![78 \leq x \leq 82](https://tex.z-dn.net/?f=78%20%5Cleq%20x%20%5Cleq%2082)
We also know that we have 50 boxes of candles, so we multiply the above range by 50 to get the range of candles:
![3900 \leq x \leq 4100](https://tex.z-dn.net/?f=3900%20%5Cleq%20x%20%5Cleq%204100)
Finally, each candle costs $2, so we have the final range of cost:
![7800 \leq x \leq 8200](https://tex.z-dn.net/?f=7800%20%5Cleq%20x%20%5Cleq%208200)
Answer:
3.75 miles i think
Step-by-step explanation:
I'm not good at explaining things but I do know how to do the problem
5. 2x-3y=-24
x+6y=18 -> -2(x+6y=18) = -2x-12y=-36
distribute -2 ^
2x-3y=-24 x+6(-4)=18
-2x-12y=-36 x -24 = 18
0-15y= -60 +24 = +24
-15 = -15 x= 42
y = 4 (42,4)
6. x-2y=5
3x-5y=8
x-2y= 5 -> -3(x-2y=5)
-3x+6y= -15
3x-5y=8 x-2y=5
0+ 1y= 7 x-2(7)=5
1 = 1 x-14=5
y = 7 +14= +14
x = 19 (19,7