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BARSIC [14]
3 years ago
5

Your class built a tepee to use in the school play. The tepee has a diameter of 16 feet and a height of 13.5 feet. What is the v

olume? Use 3.14 for pi. Round your answer to the nearest whole number.
Mathematics
2 answers:
iragen [17]3 years ago
8 0

Answer:

904 is the right answer

Step-by-step explanation:

i also got it right on imagine math

bixtya [17]3 years ago
4 0

Answer:

904 is the Answer

I got it right on imagine math

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The makers of Mini-Oats cereal have an automated packaging machine that is set to fill boxes with 24 ounces of cereal. At variou
Butoxors [25]

Answer:

1. A is the null hypothesis. The null hypothesis is the statement in which everything is operating as expected; nothing unusual is going on.

2. C is the alternative hypothesis. The problem says that you are looking to see whether or not the machine is filling with an average of 24 ounces, so it could be over or under filling. B only accounts for under filling.

Step-by-step explanation:

3 0
3 years ago
A solution of the equation 3x + y = 15?
Tamiku [17]

Step-by-step explanation:

Since there is 2 unknown variable ,

so we need 2 equation to find their values.

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1 year ago
What are the zeros of the function <br> f(x)= x^2+7x−18?<br>  <br> Enter your answers in the boxes.
olga55 [171]
The zeros of the function are x=2,-9
5 0
3 years ago
Solve for x <br> x(6x+1)= 2
Montano1993 [528]

Answer:

x=1/2,-2/3

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
3. Which of the following quadratic equations has no solution? A) 0 = −2(x − 5)2 + 3 B) 0 = −2(x − 5)(x + 3) C) 0 = 2(x − 5)2 +
klemol [59]

Answer:

D) 0 = 2(x + 5)(x + 3)

Step-by-step explanation:

Which of the following quadratic equations has no solution?

We have to solve the Quadratic equation for all the options in other to get a positive value as a solution for x.

A) 0 = −2(x − 5)2 + 3

0 = -2(x - 5) × 5

0 = (-2x + 10) × 5

0 = -10x + 50

10x = 50

x = 50/10

x = 5

Option A has a solution of 5

B) 0 = −2(x − 5)(x + 3)

Take each of the factors and equate them to zero

-2 = 0

= 0

x - 5 = 0

x = 5

x + 3 = 0

x = -3

Option B has a solution by one of its factors as a positive value of 5

C) 0 = 2(x − 5)2 + 3

0 = 2(x - 5) × 5

0 = (2x -10) × 5

0 = 10x -50

-10x = -50

x = -50/-10

x = 5

Option C has a solution of 5

D) 0 = 2(x + 5)(x + 3)

Take each of the factors and equate to zero

0 = 2

= 0

x + 5 = 0

x = -5

x + 3 = 0

x = -3

For option D, all the values of x are 0, or negative values of -5 and -3.

Therefore the Quadratic Equation for option D has no solution.

3 0
3 years ago
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