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jeyben [28]
3 years ago
13

D-10-2d+7=8+d-10-3d

Mathematics
1 answer:
TEA [102]3 years ago
4 0

Solution,solve\:for\:d,\:d-10-2d+7=8+d-10-3d\quad :\quad d=1

Steps:

d-10-2d+7=8+d-10-3d

\mathrm{Subtract\:}d-10\mathrm{\:from\:both\:sides},\\d-10-2d+7-\left(d-10\right)=8+d-10-3d-\left(d-10\right)

\mathrm{Refine},\\-2d+7=8-3d

\mathrm{Subtract\:}7\mathrm{\:from\:both\:sides},\\-2d+7-7=8-3d-7

\mathrm{Simplify},\\-2d=-3d+1

\mathrm{Add\:}3d\mathrm{\:to\:both\:sides},\\-2d+3d=-3d+1+3d

\mathrm{Simplify},\\d=1

\mathrm{The\:Correct\:Answer\:is\:d=1}

\mathrm{Hope\:This\:Helps!!!}

\mathrm{-Austint1414}

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