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anzhelika [568]
3 years ago
15

Solve for x. 38(2x+16)−2=13

Mathematics
2 answers:
Lina20 [59]3 years ago
6 0

76x+608-2=13

76x+606=13

76x= -593

x= -7.8

Anastaziya [24]3 years ago
3 0

How to get answer:

Step 1: Simplify both sides of the equation.

38(2x+16)−2=13

(38)(2x)+(38)(16)+−2=13(Distribute)

76x+608+−2=13

(76x)+(608+−2)=13(Combine Like Terms)

76x+606=13

76x+606=13

Step 2: Subtract 606 from both sides.

76x+606−606=13−606

76x=−593

Step 3: Divide both sides by 76.

\frac{76x}{76} = \frac{-593}{76}

Answer:

Decimal Form: −7.80263157…

Fraction Form: \frac{-593}{76}

Mixed Number Form: -7\frac{61}{76}

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The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha
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Answer:

The average value of f over the interval [-2,5] is \frac{10}{7}.

Step-by-step explanation:

Let suppose that function f is continuous and integrable in the given intervals, by integral definition of average we have that:

\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6 (1)

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By Fundamental Theorems of Calculus we expand both expressions:

\frac{F(3)-F(-2)}{3-(-2)} = -6

F(3) - F(-2) = -30 (1b)

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We obtain the average value of f over the interval [-2, 5] by algebraic handling:

F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)

F(5) - F(-2) = 10

\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}

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The average value of f over the interval [-2,5] is \frac{10}{7}.

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