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3 years ago

5

How do you write8.157 in 2 forms

2 answers:

saveliy_v [14]3 years ago

7 0

You could use 8.175 as a fration or just in word form

Yakvenalex [24]3 years ago

4 0

Eight point one, five, seven.
Or you could write it like: 8 plus point one, five, seven :)

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help me please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Sunny_sXe [5.5K]

So thi sis really simple since you have an equal sign so

(n/3)-(5n/6)=1/3
to subtract fractions, make the bottom number the same
n/3 times 2/2=2n/6
(2n/6)-(5n/6) or (2n-5n)/6 so
-3n/6=1/3
multiply both sides by 6
-3n=6/3=2
-3n=2
divide both sides by 3
-n=2/3
mmultiply boht by -1
n=-2/3
tada
n=-2/3

6 0

3 years ago

Read 2 more answers

Dan paid $34.30 for a sweater. The price included a 40% markup. Find the cost of the sweater before the markup was added.

Nikolay [14]

140% = $34.30
1$ = 0.245
100% = 0.245 x 100 =$24.50

The cost of the sweater os $24.50

6 0

3 years ago

What is the length of v? Type the number only. Do not include in

never [62]

Answer:

1

Step-by-step explanation:

8 0

3 years ago

Which number is a factor of 24 but not a multiple of 2

Scrat [10]

Answer: 3

Step-by-step explanation:

Since 24 is divisible by 3, we say 24 is a multiple of 3.

24 is also a multiple of 1, 2, 3, 4, 6, 8, 12, and 24.

I hope this help.

3 0

3 years ago

Read 2 more answers

Which of the following is true of the location of an angle, Theta, whose tangent value is Negative StartFraction StartRoot 3 End

Anuta_ua [19.1K]

The value of theta has a 30-degree reference angle and is located in Quadrant II or IV.

Given to us

$tan \theta =-\dfrac{\sqrt{3}}{3}$

<h3>What is the value of $tan \theta =\dfrac{\sqrt{3}}{3}$ ?</h3>

To know the value $tan \theta =\dfrac{\sqrt{3}}{3}$ we will simplify the given expression,

$tan \theta =\dfrac{\sqrt{3}}{3}\\\\\\tan \theta =\dfrac{1}{\sqrt{3}}\\\\tan \theta =30^o$

Hence, the value of theta is 30°.

<h3>Finding the location of the - tan30°?</h3>

To know that the location of the -tan30°,

$tan30^o = -\dfrac{sin30^o}{cos30^o}$

As the value is negative, therefore, there can be two cases,

Case I: when the value of Sin30° is negative,

Case II: when the value of cos30° is negative.

Case I: when the value of Sin30° is negative,

If the value of Sin30° is negative, while the value of cos30° is positive, the θ will lie in the fourth quadrant.

Case II: when the value of Cos30° is negative,

If the value of Cos30° is negative, while the value of Sin30° is positive, the θ will lie in the second quadrant.

Hence, the value of theta has a 30-degree reference angle and is located in Quadrant II or IV.

Learn more about Quadrants:

brainly.com/question/350459

5 0

3 years ago