Answer:
The dog will catch the cat at time greater than 33.33 sec
Step-by-step explanation:
Let
x------> distance the cat runs before being caught by the dog, if they started running towards each other simultaneously
Remember that
The speed is equal to divide the distance by the time
v=d/t
solve for t
t=d/v
so
equate the time
x/24=(200+x)/30
30x=24(200+x)
30x=4,800+24x
30x-24x=4,800
x=4,800/6=800 m
t=d/v=800/24=33.33 sec
or
t=(800+200)/30=1,000/30=33.33 sec
Remember that
the dog starts running after the cat
therefore
The dog will catch the cat at time greater than 33.33 sec
