Answer:
35 possible combinations would be there.
Step-by-step explanation:
We have total of seven students we have to choose three out of those seven
n is the total possibilities n =7 in the given case
And r is the chosen ones
Hence, r=3 in the given case.
Substituting the values of n and r in the formula we get
Using n!=n(n-1)----1
Cancel the common factor we get
possible combinations would be there.
Answer:
arcLP = 19
Step-by-step explanation:
Given the following
arcLM = 8x-56
arcNP = 5x+22
Required
arcLP
Given that arcLM = arcNP
8x-56 = 5x+22
8x - 5x = 22 + 56
3x = 78
x = 78/3
x = 26
Let assume arcLP = x - 7
arcLP = 26 -7
arcLP = 19
Answer:
Notebooks cost $2.75 and pens cost $1.10.
He can also buy 3 notebooks.
Step-by-step explanation:
In order to find this, we need to create two equations given each of the situations.
3n + 2p = 10.45
4n + 6p = 17.60
Now to solve for n, multiply the top equation by -3 and add together.
-9n - 6p = -31.35
4n + 6p = 17.60
----------------------
-5n = -13.75
n = 2.75
Now that we have the value of notebooks, we can find the amount for pens using either equation.
3n + 2p = 10.45
3(2.75) + 2p = 10.45
8.25 + 2p = 10.45
2p = 2.20
p = 1.10
Finally, to find the number of notebooks that he can purchase, find the cost of a notebook with 3 pens.
n + 3p
2.75 + 3(1.10)
2.75 + 3.30
6.05
Now divide 22 by that number
22/6.05 = 3.63
Since we can't have fractional notebooks, we round down to 3.
(cos2x+cos6x)(cos2x-cos6x) =
(2 sin 4x cos 4x) (2 sin 2x cos 2x) =
sin 8x sin 4x (Answer)
