Answer:
Theoretical 32.04 g
The precent yeild 87. 39 %
Explanation:
Mole of H2 = m/mw = 4/2 = 2 mol
From the equation
1 mol H2 --> 1/2 mol CH3OH
2 mol H2 -->??
So we have 1 mol Ch3oh
Mass of Ch3oh = mole *Mw = 1* 32.04
= 32.04g >>> the theoretically
For percent yeild = actual / theoretical * 100%
( 28.0/32.04) *100% =
87.93%
X equals <span>2.76923076923</span>
In order to find the molarity of the solution, we first require the moles of acetic acid added. For this,we need the mass which is:
Mass = volume * density
Mass = 50 * 1.05
Mass = 52.5 grams
Moles = mass / molecular weight
Moles = 52.5 / 60.05
Moles = 0.874 mol
Next, we know that the molarity of a solution is:
Molarity = moles / liter
Molarity = 0.874 / 0.5
Molarity = 1.75 M
Answer is: 230 g.
Chemical reaction: P₄ + 5O₂ → 2P₂O₅.
m(P₄) = 100 g.
M(P₄) = 4 · 31 g/mol = 124 g/mol.
n(P₄) = m(P₄) ÷ M(P₄) = 100g ÷ 124g/mol = 0,806 mol.
From reaction: n(P₄) : n(P₂O5) = 1 : 2.
n(P₂O₅) = 1,612 mol.
m(P₂O₅) = 1,612 mol · 142g/mol = 230g.
M - molar mass.
n - amount of substance.