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3 years ago

How did the Bohr model of the atom affect scientific thought?

Chemistry

2 answers:

Neporo4naja [7]3 years ago

6 0

Answer:

Its a.

Explanation:

Vadim26 [7]3 years ago

5 0

Answer:

C. Scientists accepted the model at first but later rejected it.

Explanation:

Scientists accepted the model at first because it explained the hydrogen emission spectrum.

However, with the development of quantum mechanics, scientists had to modify the model (not reject it).

Electrons still had specific energies, but they no longer travelled in fixed orbits.

Instead, electrons had a probability of being found in a given region of space.

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You discover some bones that have roughly %s as much carbon-14 in them as

Dafna1 [17]

Answer:

150 years i guess so? im nkt sure

4 0

3 years ago

Read 2 more answers

If 1.00 g of a hydrocarbon is combusted and found to produce 3.14 g of co2, what is the empirical formula of the hydrocarbon?

photoshop1234 [79]

The combustion reaction is as expressed,

CxHy + O2 --> CO2 + H2O

The mass fraction of carbon in CO2 is 3/11. Hence,
mass of C in CO2 = (3.14 g)(3/11) = 0.86 g C.

Given that we have 1 g of the hydrocarbon, the mass of H is equal to 0.14 g.

moles of C = 0.86 g C / 12 g = 0.0713
moles of H = 0.14 g H / 1 g = 0.14

The empirical formula for the hydrocarbon is therefore, CH₂.

7 0

3 years ago

The combustion of glucose (c6h12o6) with oxygen gas produces carbon dioxide and water. this process releases 2803 kj per mole of

V125BC [204]

Answer:- 335 kcal of heat energy is produced.

Solution:- The balanced equation for the combustion of glucose in presence of oxygen to give carbon dioxide and water is:

$C_6H_1_2O_6+6O_2\rightarrow 6CO_2+6H_2O$

From given info, 2803 kJ of heat is released bu the combustion of 1 mol of glucose. We need to calculate the energy produced when 3.00 moles of oxygen react with excess of glucose.

We could solve this using dimensional analysis as:

$3.00mol O_2(\frac{1mol glucose}{6mol O_2})(\frac{2803 kJ}{1mol glucose})$

= 1401.5 kJ

Now, let's convert kJ to kcal.

We know that, 1kcal = 4.184kJ

So, $1401.5kJ(\frac{1kcal}{4.184kJ})$

= 335 kcal

Hence, 335 kcal of heat energy is produced by the use of 3.00 moles of oxygen gas.

8 0

3 years ago

A chemist must dilute 61.9 mL of 548. nM aqueous sodium carbonate (Na2CO3) solution until the concentration falls to 484. nM . H

maw [93]

Answer:

The final volume will be "70.08 mL".

Explanation:

The given values are:

Molar mass,

M1 = 548 nM

or,

= $5.48\times 10^{-7} \ M$

M2 = 484 nM

or,

= $4.84\times 10^{-7} \ M$

Volume,

V1 = 61.9 mL

V1 = ?

By using the expression, we get

⇒ $M1\times V1=M2\times V2$

or,

⇒ $V2=\frac{M1\times V1}{M2}$

By substituting the values, we get

$=\frac{5.48\times 10^{-7}\times 61.9}{4.84\times 10^{-7}}$

$=\frac{339.212}{4.84}$

$=70.08 \ mL$

7 0

3 years ago

10. Translate each of the following chemical equations into a sentence.

Fofino [41]

Answer:

a) $2ZnS(s)+3O_2(g)\rightarrow 2ZnO(s)+2SO_2(g)$

2 moles of Zinc sulphide in solid form reacts with 3 moles of Oxygen in gaseous form to give 2 moles of Zinc oxide in solid form and 2 moles of sulphur dioxide in gaseous form.

b) $CaH_2(s)+2H_2O(l)\rightarrow Ca(OH)_2 aq)+2H_2(g)$

1 mole of calcium hydride in solid form reacts with 2 moles of liquid water to give 1 mole of calcium hydroxide dissolved in water and 2 moles of hydrogen in gaseous form.

The chemical reactions are written by writing the chemical formula of the reactants on left side of the arrow followed by chemical formula of the products. The number of atoms of each element must be balanced to follow the law of conservation of mass.

8 0

3 years ago