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svp [43]
3 years ago
10

A) A sample of ideal gas is in a sealed container. The pressure of the gas is 725 torr, and the temperature is 18 ∘C. If the tem

perature changes to 75 ∘C with no change in volume or amount of gas, what is the new pressure, P2, of the gas inside the container? Express your answer with the appropriate units.
b) Using the same sample of gas (P1
= 725 torr, T1 = 18 ∘C ), we wish to change the pressure to 7250 torr with no accompanying change in volume or amount of gas. What temperature T2, in Celsius, is needed to reach this pressure? Express your answer with the appropriate units.
Chemistry
1 answer:
Fudgin [204]3 years ago
8 0

Answer:

a. The new pressure is 606,25 Torr.

b. -243,9°C is needed to reach the pressure of 7250 Torr.

Explanation:

Gay Lussac's law for gases says that if the volume in a gas remains constant, the pressure will be directly proportional to the temperature change.

P1 . T1 = P2. T2

(Temperature must be in K)

725 Torr . 291 K = P2 . 348 K

(725 Torr . 291 K) /348 K = P2

606,25 Torr = P2

725 Torr . 291K = 7250 Torr . T2

(725 Torr . 291K) /7250 Torr = T2

29,1 K = T2

T° K - 273 = T°C

29,1 K -273 = -243,9°C

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I NEED HELP ASAP! PLEASE BE GENUINE
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1. The molar mass of the unknown gas obtained is 0.096 g/mol

2. The pressure of the oxygen gas in the tank is 1.524 atm

<h3>Graham's law of diffusion </h3>

This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e

R ∝ 1/ √M

R₁/R₂ = √(M₂/M₁)

<h3>1. How to determine the molar mass of the gas </h3>
  • Rate of unknown gas (R₁) = 11.1 mins
  • Rate of H₂ (R₂) = 2.42 mins
  • Molar mass of H₂ (M₂) = 2.02 g/mol
  • Molar mass of unknown gas (M₁) =?

R₁/R₂ = √(M₂/M₁)

11.1 / 2.42 = √(2.02 / M₁)

Square both side

(11.1 / 2.42)² = 2.02 / M₁

Cross multiply

(11.1 / 2.42)² × M₁ = 2.02

Divide both side by (11.1 / 2.42)²

M₁ = 2.02 / (11.1 / 2.42)²

M₁ = 0.096 g/mol

<h3>2. How to determine the pressure of O₂</h3>

From the question given above, the following data were obtained:

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  • Temperature (T) = 21 °C = 21 + 273 = 294 K
  • Gas constant (R) = 0.0821 atm.L/Kmol
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The pressure of the gas can be obtained by using the ideal gas equation as illustrated below:

PV = nRT

Divide both side by V

P = nRT / V

P = (27.65625 × 0.0821 × 294) / 438

P = 1.524 atm

Learn more about Graham's law of diffusion:

brainly.com/question/14004529

Learn more about ideal gas equation:

brainly.com/question/4147359

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