Answer:
y = 2/3x +6 for x< -3
y = 2/3x +1 for x> 3
Step-by-step explanation:
The graph is a line for x < -3
( - 6,2) and ( -3,4)
The slope is m= ( y2-y1)/(x2-x1)
m = ( 4-2)/(-3 - -6) = 2/ ( -3+6) = 2/3
The slope is 2/3
Using point slope form
y-y1 = m(x-x1) and the point ( -6,2)
y -2 = 2/3(x - -6)
y -2 = 2/3(x +6)
y-2 = 2/3 x +4
y = 2/3x +6 x< -3
The graph is a line for x > 3
(3,3) and ( 6,5)
The slope is m= ( y2-y1)/(x2-x1)
m = ( 5-3)/(6-3) = 2/ (3) = 2/3
The slope is 2/3
Using point slope form
y-y1 = m(x-x1) and the point (6,5)
y -5 = 2/3(x - 6)
y-5 = 2/3 x -4
y = 2/3x +1 x> 3
Answer:
1/3
Step-by-step explanation:
When working with balanced expressions (stuff on both sides of the equal sign), "what you do to one side, you do to the other", which keeps it balanced.
The first thing we notice is the exponent 1/4, which is one both sides, so we can get rid of it on both sides by using the <u>reverse operation</u>.
The reverse of exponents is <u>square root</u>.
![(4x + 10)^{\frac{1}{4}} = (9 + 7x)^{\frac{1}{4}}\\\sqrt[\frac{1}{4}]{(4x + 10)^{\frac{1}{4}}} = \sqrt[\frac{1}{4}]{(9 + 7x)^{\frac{1}{4}}}\\\\4x + 10 = 9 + 7x](https://tex.z-dn.net/?f=%284x%20%2B%2010%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%20%3D%20%289%20%2B%207x%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%5C%5C%5Csqrt%5B%5Cfrac%7B1%7D%7B4%7D%5D%7B%284x%20%2B%2010%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%7D%20%3D%20%5Csqrt%5B%5Cfrac%7B1%7D%7B4%7D%5D%7B%289%20%2B%207x%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%7D%5C%5C%5C%5C4x%20%2B%2010%20%3D%209%20%2B%207x)
Isolate x to solve. Separate the variables and non-variables.
4x + 10 = 9 + 7x
4x - 4x + 10 = 9 + 7x - 4x Subtract 4x from both sides
10 = 9 + 3x
10 - 9 = 9 - 9 + 3x Subtract 9 from both sides
1 = 3x Divide both sides by 3 to isolate x
x = 1/3 Answer
Answer:
x = 21
Step-by-step explanation:
The 2 angles form a straight angle and are supplementary, thus
7x + 9 + 2x - 18 = 180, that is
9x - 9 = 180 ( add 9 to both sides )
9x = 189 ( divide both sides by 9 )
x = 21
Answer:
198 cm²
Step-by-step explanation:
We are given the dimensions of a rectangular prism;
3cm 9cm and 6cm
We are required to determine its surface area;
We need to know that;
Surface area of a rectangular prism is given by;
A = 2(WL+HL+WH)
Where L, W and H are length , width and height respectively;
Assuming;
Width is 3 cm
Length is 9 cm, and
Height is 6 cm
Then;
Area = 2 ( (3×9) + (6×9) + (3×6))
= 2(99)
= 198 cm²
Therefore, the area of the rectangular prism is 198 cm²
1080 dollars. The first interest is 2700 and the second is 1620.
