Answer:
28/55
Step-by-step explanation:
total no of beads are 11
red beads are 7
and white beads are 4
no of ways to take 2 beads from 11 beads are 11c2
that is( 11*10)/2=55
no of ways to take 1 red bead from 7 is 7c1 that is 7
no of ways to take 1 white bead from 4 is 4c1 is that is 4
required probability is( 7*4)/55=28/55
this question has already been answered on someone else's account so know this answer is 100% correct
hope that helped :)
Answer:
x^(5/6) + 4(x^(7/3))
Step-by-step explanation:
Simplify x to the 1/3 power MULTIPLIED BY (x to the 1/2 power + 2x to the 2 power )
Simplify x^(1/3) × (x^(1/2) + (2x)^2)
= x^(1/3)(x^(1/2)) + x^(1/3)((2x)^2)
= x^(1/3+1/2) + 4(x^(1/3+2))
= x^(5/6) + 4(x^(7/3))
x^(1/3) is y such that y^3 = x
(x^(1/3) × x^(1/3) × x^(1/3)) = x^(1/3+1/3+1/3) = x^1 = x
x^(1/2) = √2 = y such that y^2 = x
(2x)^2 = 4x^2
1/x^2. Remember that any number raised to a negative power is the reciprocal.
25 bags have zips on them
