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tiny-mole [99]
3 years ago
6

PLEASE HELP ASAP, I WILL MARK THE BRAINLIEST

Mathematics
1 answer:
dlinn [17]3 years ago
8 0

Answer:

the answer is c now mark me brainliest please.

Step-by-step explanation:

all sides are congruent and it is a parallelogram.

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Given f(x) = 4x^4 find f^-1(x) Then state whether f^-1(x) is a function.
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Answer:

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Step-by-step explanation:

To find the inverse function, solve for y:

x=f(y)\\\\x=4y^4\\\\\dfrac{x}{4}=y^4\\\\\pm\sqrt[4]{\dfrac{x}{4}}=y\\\\f^{-1}(x)=\pm\sqrt[4]{\dfrac{x}{4}}

f(x) is an even function, so f(-x) = f(x). Then the inverse relation is double-valued: for any given y, there can be either of two x-values that will give that result.

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A function is single-valued. That means any given domain value maps to exactly one range value. The test of this is the "vertical line test." If a vertical line intersects the graph in more than one point, then that x-value maps to more than one y-value.

The horizontal line test is similar. It is used to determine whether a function has an inverse function. If a horizontal line intersects the graph in more than one place, the inverse relation is not a function.

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Since the inverse relation for the given f(x) maps every x to two y-values, it is not a function. You can also tell this by the fact that f(x) is an even function, so does not pass the horizontal line test. When f(x) doesn't pass the horizontal line test, f^-1(x) cannot pass the vertical line test.

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The attached graph shows the inverse relation (called f₁(x)). It also shows a vertical line intersecting that graph in more than one place.

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Step-by-step explanation:

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