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Artemon [7]
3 years ago
13

1. Put 9y=-3x-39 into standard form

Mathematics
2 answers:
Kruka [31]3 years ago
5 0
1. 9y = -3x - 39....add 3x to both sides
    3x + 9y = -39 <== standard form

2. -2x + 2y = -2. ..multiply by -1
     2x - 2y = 2 <== standard form

3. -2x = 20
     x = -20/2
     x = -10....now sub this back into the second equation

     3x - 4y = -2
    3(-10) - 4y = -2
    -30 - 4y = -2
     -4y = -2 + 30
     -4y = 28
      y = -28/4
      y = -7

solution is (-10,-7) <== solution
Montano1993 [528]3 years ago
3 0
<span>1. Put 9y=-3x-39 into standard form 
           3x + 9y = -39 ...this is standard form

2. Put -2x+2y=-2 into standard form
           2x - 2y = 2 </span> ...this is standard form
<span>
3. Solve the system by either using substitution or elimination
{-2x=20, 3x-4y=-2}

-2x = 20
   x = -10

substitute x = -10 into  </span>3x-4y=-2

3x-4y=-2
3(-10)-4y=-2
-30 - 4y = -2
4y = -28
  y = -7

answer
x = -10 and y = -7
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Using translation concepts, it is found that the transformations to create function d are given as follows:

  • Horizontal shift right 1 unit.
  • Vertical shift up 5 units.
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<h3>What is a translation?</h3>

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

In this problem, the parent cosine function is given by:

f(x) = cos(x).

The translated function is given by:

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Which means that:

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More can be learned about translation concepts at brainly.com/question/4521517

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