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spin [16.1K]
3 years ago
13

What is the inverse of the function f(x)= 1/4x - 12?

Mathematics
1 answer:
Zolol [24]3 years ago
6 0
-12+1/4x= f(x) the f(x) can go on either side
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Will give Brainliest! if right!
Bogdan [553]
There are 11 letters in total.
T & B 
T = 1/11
B = 2/11
The total probability is 3/11.
6 0
3 years ago
While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem
Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

So, Null Hypothesis, H_0 : p = 0.013      {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, H_A : p > 0.013      {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion faulty modems= \frac{10}{367} = 0.027

           n = sample of modems = 367

So, <u><em>the test statistics</em></u>  =  \frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }

                                     =  2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0
3 years ago
In the figure, ∠1 ≅ ∠2, ∠3 ≅ ∠4, and . You can justify the conclusion that ∠TKL ≅ ∠TLK by stating _____
VladimirAG [237]
From the question, we know that we will be looking at <3, <4, and angles TKL and TLK. That being said, since <3 is congruent to <4, that means that angles TKL and TLK, which are each supplementary to either angle 3 or 4, are congruent because, since angles 3 and 4 are congruent, they are congruent because the supplements of congruent angles are congruent. 
3 0
2 years ago
Read 2 more answers
Find the rate of change given the following solutions: (6, 2) and (1, 12).
blagie [28]

Answer:

The rate of change is -2

Step-by-step explanation:

f(b)-f(a)     12-2              10

---------- = ------------  = -------- = -2

 b-a         1-6               -5

7 0
2 years ago
Factorise x²-49<br>please solve this answer​
Degger [83]

Answer:

(x+7)(x-7)

Step-by-step explanation:

x²-49

=x²-7²

=(x+7)(x-7)

4 0
3 years ago
Read 2 more answers
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