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Kay [80]
3 years ago
14

PLEASE HURRY PLEASE PLEASE PLEASE

Mathematics
1 answer:
hram777 [196]3 years ago
3 0

Answer:

b

Step-by-step explanation:

make a formula, its the easiest way to solve problems like these also its very efficent

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You can use a bar diagram to help you write the equation of a linear function.
Svet_ta [14]

Answer:

idk but I hope you the best of luck

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The product of 4 and a number ,increased by 22 is 146. What is the number ?
maks197457 [2]
Not absolutely sure I understand the question, but should be 120
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Jennifer has $50 in her bank account. She deposits $15 per week. Write a linear
Romashka [77]

Answer:

y=-15x+50

Step-by-step explanation:

You originally had 50 dollars, so +50. Then, it decreases at a rate of 15 every week, so -15x.

Y is the total number of money she has.

y= -15x+50

4 0
3 years ago
Read 2 more answers
Kristen invests $5,745 in a bank. The bank pays 6.5% interest compounded monthly. How long must she leave the money in the bank
s344n2d4d5 [400]

formula is A=P(1-\frac{r}{n})^{nt}

where A=final amount

P=principal

r=interest rate in decimal

n=number of times per year it is compounded

t=time in years


we want to find where

A=2P

and P=5745

and r=6.5%=0.065

n=monthly=12


remember that ln(x^a)=a(ln(x))

also that (a^b)^c=a^{bc}

2(5745)=5745(1+\frac{0.065}{12})^{12t}, solving for t

divide both sides by 5745 to simplify things a bit

2=(1+\frac{0.065}{12})^{12t} I'd rather not simplify this because it give us a decimals and those aren't exact, if we combine, we get 12.065/12 for inside parenthases

2=(\frac{12.065}{12})^{12t}

take ln of both sides

ln(2)=ln((\frac{12.065}{12})^{12t})

ln(2)=(12t)ln(\frac{12.065}{12})

divide both sides by 12ln(\frac{12.065}{12})

\frac{ln(2)}{12ln(\frac{12.065}{12})}=t

using our calculator, t≈10.6927


so rounded, we get 10.7 years

3 0
3 years ago
A box contains 1 3/4 Pasta how many ounces of pasta are in the box
Ostrovityanka [42]

Answer:

Step-by-step explanation:

is there more information to the question??

7 0
2 years ago
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