Answer:
Step-by-step explanation:
subtracting 3 from both sides
3
x
−
9
=
0
3
x
−
9
+
9
=
0
+
9
Adding 9 to both sides
3
x
=
9
3
x
3=9
3
Dividing both sides by 3
should give you 3
Answer:
x ≥6
Step-by-step explanation:
Given the product:
√(x-6)*√(x+3)
The function has to be defined if x ≥0
Hence;
√(x-6)*√(x+3)≥0
Find the product
√(x-6)(x+3)≥0
Square both sides
(x-6)(x+3)≥0
x-6≥0 and x+3≥0
x≥0+6 and x ≥0 - 3
x ≥6 and x ≥-3
Hence the required inequality is x ≥6
-6 - 6(4)
-6 -24 = -30
So -30 is ur answer :)) hope I helped
Hello,
f(x)=2x^3-x^2-4x+9=(((0+2)x-1)x-4)x+9
f(3)=(((0+2)*3-1)*3-4)*3+9=((2*3-1)*3-4)-3+9=(5*3-4)*3+9=11*3+9=33+9=42
or
f(3)=2*3^3-3^2-4*3+9=2*27-9-12+9=54-12=42
