<span>To find the number of nickels and dimes, we can use this equation: 0.10d + 0.05n = 5.25
We are given the information that Sonji has 21 dimes (which means that d=21). We can use the equation to find the number of nickels n.
0.10d + 0.05n = 5.25
0.10(21) + 0.05n = 5.25
2.10 + 0.05n = 5.25
0.05n = 3.15
n = 3.15 / 0.05
n = 315 / 5
n = 63
Sonji has 63 nickels.
Let's check our answer.
21(0.10) + 63(0.05) = 2.10 + 3.15 = 5.25
It seems that our answer is correct.</span>
9514 1404 393
Answer:
(a) ❘-270 - 30❘
Step-by-step explanation:
One score is -270 and the other is +30. The difference is either of ...
|30 -(-270)|
or
|-270 -30| . . . . . . matches choice A
Part A) x-intercepts simply show that when the value of the function is zero. Vertex coordinates show that when the function obtains its maximum value. When x=50, function obtains its maximum value and it's 75. The function is increasing in the interval (0, 50) and decreasing in the interval (50, 100). In regard to the height and distance of the tunnel, these numbers show that decreasing and increasing intervals are symmetric. Each number from the intervals has its own pair in the corresponding interval and they are located in the same distance from the midpoint (50,75)
Part B) In order to calculate the average rate of change, we can first write the function. Using the information about the x-intercept and the vertex coordinates, we find that our function is

.
Plugging 15 and 35 in x, we can find the values of the function, i.e.

and

.
Then, the average change is
Answer:
1 pm
Step-by-step explanation:
We have to find their LCM, or least common multiple
Multiples of 36: 36, 72, 108, 144, 180, 216, ......
Multiples of 45: 45, 90, 135, 180, ....
180 mins is their LCM.
180 mins = 3 hours
10am + 3hours = 1 pm
-Chetan K
Using BEDMAS, it would be brackets first, so anything Inside a set of brackets would be solved first, and would follow the same rule. Once the brackets have been solved, next would be the exponents. Since your brackets have been solved you can expand with the exponents. After exponents, would be anything that has to be divided or multiplied. These two operations are interchangeable based on what is more convenient or beneficial to do first. And lastly, addition and subtraction, which once again are interchangeable operations