Find A cup(B cap C) . A = \{1, 4, 6, 7\}; B = \{3, 4, 5\}; C = \{2, 4, 8\}; \{1, 4, 6, 7\} 4 } \{1, 2, 3, 4, 5, 6, 7, 8\}
Inessa05 [86]
The only common element between B and C is 4, so B ∩ C = {4}.
4 is also already contained in A, so B ∩ C is a subset of A, and thus
A U (B ∩ C) = A = {1, 4, 6, 7}
Given:
The polynomials are:
To find:
The completely simplified sum of the polynomials.
Solution:
We have,
The sum of given polynomials is:
Therefore, the sum of the given polynomials is 
. It is a polynomial with degree 6 and leading coefficient -2.
Actually, this answer would be true. Why?
The first equation is: a(sub <em>n</em>) = 8, 13, 18, 23
The second is: a(sub 1)=8 ; a(sub <em>n</em>)= a(sub <em>n</em>-1)+5
if you wish to find the second term, plug two into the equation for <em /><em>n</em>
8+5=13
to find the third, plug the second term, 13, in for <em>n.</em>
13+5=18.
Hope this helped! I know it's a bit on the late side, but at least you can get the general idea!
