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Fittoniya [83]
3 years ago
11

What is the approximate are of the shaded region's?

Mathematics
1 answer:
bixtya [17]3 years ago
4 0

Calculate the area of the squares and the area of the circles, then subtract the area of the circle from the square.

Square with 14 m side:

Area of square = 14 x 14 = 196 square m.

Area of circle inside: 3.14 x 7^2 = 3.14 x 49 = 153.86 square m.

Area of shaded region: 196 - 153.86 = 42.14 square m.

Square with 8 m side:

Area of square: 8 x 8 = 64 square m.

Area of circle: 3.14 x 4^2 = 3.14 x 16 = 50.24 square m.

Area of shaded region: 64 - 50.24 = 13.76 square m.

Round answers as needed.

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Using a scale of 1 to 10 billion model solar system, what is the diameter and distance from the sun using diameter of 4880km and
Yuki888 [10]

Answer:

Diameter Orbit Radius   Diameter Orbit Radius

average average   average average

km km   cm km

1,392,000   Sun 13,920,000,000  

4,879 57,910,000 Mercury 48,790,000 5,791,000

12,100 108,200,000 Venus 121,000,000 10,820,000

12,740 149,600,000 Earth 127,400,000 14,960,000

6,779 227,900,000 Mars 67,790,000 22,790,000

950.0 413,800,000 Ceres

Asteroid Belt 9,500,000 41,380,000

139,800 778,600,000 Jupiter 1,398,000,000 77,860,000

116,500 1,433,000,000 Saturn 1,165,000,000 143,300,000

50,720 2,877,000,000 Uranus 507,200,000 287,700,000

49,250 4,503,000,000 Neptune 492,500,000 450,300,000

2,372 5,874,000,000 Pluto

Kuiper Belt 23,720,000 587,400,000

Step-by-step explanation:

5 0
3 years ago
What is an written expression for 20+5×9
BartSMP [9]

Answer:

Five times nine plus twenty

Step-by-step explanation:

Just remember the order of operations... multiplication and division are done first before adding and subtracting.

7 0
4 years ago
Can someone plzz help me with these two answers?
galina1969 [7]
The answer to #5 is 171
The answer to #6 is -344
8 0
3 years ago
N/5 greater than or equal to 11
avanturin [10]
N/5 is greater than 11
5 0
3 years ago
Fill in the blank with a constant, so that the resulting expression can be factored as the product of two linear expressions: 2a
sdas [7]

Answer:

-15

Step-by-step explanation:

We proceed as follows;

In this question, we want to fill in the blank so that we can have the resulting expression expressed as the product of two different linear expressions.

Now, what to do here is that, when we factor the first two expressions, we need the same kind of expression to be present in the second bracket.

Thus, we have;

2a(b-3) + 5b + _

Now, putting -15 will give us the same expression in the first bracket and this gives us the following;

2a(b-3) + 5b-15

2a(b-3) + 5(b-3)

So we can have ; (2a+5)(b-3)

Hence the constant used is -15

8 0
3 years ago
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