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3 years ago

What number is halfway between 0 and negative 20

Mathematics

2 answers:

Darina [25.2K]3 years ago

5 0

Im thinking that it is negative ten

daser333 [38]3 years ago

3 0

Negative 10 is the answer

Hope this helps!
:)

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How do I solve this problem?

Andrews [41]

so the line is dog so we know the full line is 60 units long. The 2 parts (do and og) add up to the full length so we can make the equation:

(4x-3)+(2x+21)=60

6x+18=60

6x=42

x=7

if you need to fine do or og, just plug in x to its equation

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3 years ago

7th grade math help me pleasee

irinina [24]

Answer:

15 degrees Celsius

Step-by-step explanation:

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2 years ago

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Write a word phrase for 25-0.6x

ahrayia [7]

Answer:

twentyfive minus 6tenths multiplied

Step-by-step explanation:

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3 0

3 years ago

The sphere below has a radius of 2.5 inches and an approximate volume of 65.42 cubic inches.

Stells [14]

Part a: The radius of the second sphere is 5 inches.

Part b: The volume of the second sphere is 523.33 in³

Part c; The radius of the third sphere is 1.875 inches.

Part d: The volume of the third sphere is 27.59 in³

Explanation:

Given that the radius of the sphere is 2.5 inches.

Part a: We need to determine the radius of the second sphere.

Given that the second sphere has twice the radius of the given sphere.

Radius of the second sphere = 2 × 2.5 = 5 inches

Thus, the radius of the second sphere is 5 inches.

Part b: we need to determine the volume of the second sphere.

The formula to find the volume of the sphere is given by

$V=\frac{4}{3} \pi r^3$

Substituting $\pi=3.14$ and $r=5$ , we get,

$V=\frac{4}{3} (3.14)(125)$

$V=\frac{1580}{3}$

$V=523.3333 \ in^3$

Rounding off to two decimal places, we have,

$V=523.33 \ in^3$

Thus, the volume of the second sphere is 523.33 in³

Part c: We need to determine the radius of the third sphere

Given that the third sphere has a diameter that is three-fourths of the diameter of the given sphere.

Hence, we have,

Diameter of the third sphere = $\frac{3}{4} (5)=3.75$

Radius of the third sphere = $\frac{3.75}{2} =1.875$

Thus, the radius of the third sphere is 1.875 inches

Part d: We need to determine the volume of the third sphere

The formula to find the volume of the sphere is given by

$V=\frac{4}{3} \pi r^3$

Substituting $\pi=3.14$ and $r=1.875$ , we get,

$V=\frac{4}{3} (3.14)(1.875)^3$

$V=\frac{4}{3} (3.14)(6.59)$

$V=27.5901 \ in^3$

Rounding off to two decimal places, we have,

$V=27.59 \ in^3$

Thus, the volume of the third sphere is 27.59 in³

4 0

3 years ago

Johnny earns $5 per day delivering newspapers. What equation shows how much money m he earns delivering papers for d days

4vir4ik [10]

Answer:

Step-by-step explanation: so, he earns 5 dollars every day, and he starts off with 0 with the y=mx+b form you would y or m in this case is equal to 5x or is this case d so ot would be m=5d

5 0

3 years ago