The left side was cut out but x will be on top and 5 in the lower square. The last one is the answer.
Answer:
I used this converter, very helpful
Step-by-step explanation:
Answer:
Step-by-step explanation:
We know that for two similar matrices
and
exists an invertible matrix
for which
[/tex]
∴ ![B^{T} = (P^{-1})^{T} A^{T} P^{T} \\](https://tex.z-dn.net/?f=B%5E%7BT%7D%20%3D%20%28P%5E%7B-1%7D%29%5E%7BT%7D%20A%5E%7BT%7D%20P%5E%7BT%7D%20%5C%5C)
Also ![P^{-1}P = I\\](https://tex.z-dn.net/?f=P%5E%7B-1%7DP%20%3D%20I%5C%5C)
and ![(P^{-1})^{T} = (P^{T})^{-1}](https://tex.z-dn.net/?f=%28P%5E%7B-1%7D%29%5E%7BT%7D%20%3D%20%28P%5E%7BT%7D%29%5E%7B-1%7D)
∴![(P^{-1})^{T}P^{T} = I](https://tex.z-dn.net/?f=%28P%5E%7B-1%7D%29%5E%7BT%7DP%5E%7BT%7D%20%3D%20I)
so, ![B^{T} = (P^{-1})^{T} A^{T} P^{T} = (P^{T})^{-1}A^{T} P^{T}\\B^{T} = A^{T} I\\B^{T} = A^{T}](https://tex.z-dn.net/?f=B%5E%7BT%7D%20%3D%20%28P%5E%7B-1%7D%29%5E%7BT%7D%20A%5E%7BT%7D%20P%5E%7BT%7D%20%3D%20%28P%5E%7BT%7D%29%5E%7B-1%7DA%5E%7BT%7D%20P%5E%7BT%7D%5C%5CB%5E%7BT%7D%20%3D%20A%5E%7BT%7D%20I%5C%5CB%5E%7BT%7D%20%3D%20A%5E%7BT%7D)
Given:
Scale of the map 1 1/4cm : 8 yards
Rectangular Park: width : 2 1/2 cm ; length : 6 1/4 cm
Circular Pond: pi = 3.14 ; diameter 1 1/4 cm
Convert mixed factions into fractions.
Scale 1 1/4 = (4*1+1)/4 = 5/4
Width: 2 1/2 = (2*2+1)/2 = 5/2
Length: 6 1/4 = (4*6+1)/4 = 25/4
Diameter: 1 1/4 = (4*1+1)/4 = 5/4
width / scale * 8 yds = width in yards
5/2 ÷ 5/4 = 5/2 * 4/5 = 20/10 = 2 * 8 yds = 16 yds
length / scale * 8 yds = length in yards
25/4 ÷ 5/4 = 25/4 * 4/5 = 100/20 = 5 * 8 yds = 40 yds
Area of a rectangular park = l * w = 40 yds * 16 yds = 640 yds²
diameter / scale * 8 yds = diameter in yards
5/4 ÷ 5/4 = 5/4 * 4/5 = 20/20 = 1 * 8 yds = 8 yds.
radius = d/2 = 8/2 = 4
Area of a circular pond = πr² = 3.14 * 4² = 3.14 * 16yds² = 50.24 yds²
Answer:
x + 3
Step-by-step explanation:
When you substitute the x for -3, it will equal 0. This means it's a zero of the function.