2x + 5y = -8 . . . (1)
-133x - 4y = -8 . . . (2)
(1) * 4 => 8x + 20y = -32 . . . (3)
(2) * -5 => -665x + 20y = 32 . . . (4)
(3) - (4) => 673x = 0
x = 0
From (1), 2(0) + 5y = -8
5y = -8
y = -8/5
Answer:
- y= -12
- x = 7
- q = -1
- x = 24
Step-by-step explanation:
1. ..............................................
- 6(y + 7) = 2(y - 3)
- 6y + 42 = 2y - 6
- 6y - 2y = -6 - 42
- 4y = -48
- y = -12
2...............................................
- 3x + 2(x - 5) = 25
- 3x + 2x - 10 = 25
- 5x = 25 + 10
- 5x = 35
- x = 7
3 . ..............................................
- 10q + 3q + 5 = 2(q - 3)
- 13q + 5 = 2q - 6
- 13q - 2q = -6 - 5
- 11q = -11
- q = -1
4. ..............................................
- 1/3(x + 6) = 2/3(x - 9)
- 3*1/3(x+6) = 3*2/3(x - 9)
- x + 6 = 2(x - 9)
- x + 6 = 2x - 18
- 2x - x = 6 + 18
- x = 24
Answer:
x=-1/2
Step-by-step explanation:
Given:
8x^3+12x^2+6x+1=0
Making factors of the given polynomial by using cube formula, given as
(a + b)^3 = a^3 + 3a^2b + 3ab^2 + b^3
Re-writting the given polynomial:
(2^3.x^3) + 3(2^2.x^2)(1)+3(2x)(1) + (1^3)=0
Hence (2^3.x^3) + 3(2^2.x^2)(1)+3(2x)(1) + (1^3) can be written as (2x+1)^3
(2x+1)^3= 0
2x+1= 0
2x= -1
x= -1/2 !
