Answer:
x= 5.55 and 0.45
Step-by-step explanation:
Quadratic Equation = (-b±√b²-4(a)(c))÷2(a)
Get equation = to 0 by subtracting the 3 on the right side of the = sign
2x² - 12x + 5
Identify the variables
a=2
b=-12
c=5
Put them into the quadratic equation
(-(-12)± √-12² - 4(2)(5))÷2(2)
Simplify
(12 ±√144 - 40)÷4
(12±√104)÷4
Now split into 2 equations (one with addition one with subtraction) because of the ± then continue simplifying
(12 - √104)÷4 (12 + √104)÷4
(12 - 10.198039)/4 (12 + 10.198039)/4
5.54950975 0.45049025
Round
5.55 0.45
Step-by-step explanation:
x= -2,
(x - 5) / 2= -6
( (-2) - 5) / 2= -6
(-7) / 2 = -6
-3.5 = - 6
right hand side not equal to left hand side of this equation.so,x= -2 cannot exist for this equation.
x=2,
(x - 5) / 2= -6
(2 - 5) / 2= -6
(-3) / 2= -6
-1.5 = - 6
right hand side not equal to left hand side of this equation.so,x= 2 cannot exist for this equation.
x= -17
(x - 5) / 2= -6
( ( -17) - 5) / 2= -6
(- 22) / 2= -6
-11 = -6
right hand side not equal to left hand side of this equation.so,x= -17 cannot exist for this equation.
x= -7,
(x - 5) / 2= -6
( ( -7) -5) / 2= -6
(-12) / 2= -6
-6= -6
right hand side equal to left hand side of this equation.so,x= -7 exist for this equation.
Answer:
Top right (one what has 16cm^2 and 9cm^2)
Step-by-step explanation:
The one in the top right and even though I cannot see what the area is of the biggest square, I can tell what it should be the two smaller squares combined
Hope this helps :)
