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jasenka [17]
3 years ago
6

Express

Mathematics
1 answer:
krok68 [10]3 years ago
4 0

Answer:

\frac{15}{9}  (7 + 2 \sqrt{10} )

Step-by-step explanation:

The solution is in the picture

At line 7, the denominator of the expression contains irrational number (which is surd 10). This shows that the expression is not simplified

At line 8 of my solution, multiply both numerator and denominator by the conjugate of

7 - 2 \sqrt{10}

which is

7 + 2 \sqrt{10}

in order to eliminate irrational number at denominator

More info of conjugate

The conjugate of a+b is a-b,

Why conjugate? Try it yourself!

Hint: (a+b)(a-b) = a^2 - b^2

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C. A straight path from one point to another.
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1.
PolarNik [594]
Question 1:

<span>5z – 9 = 36

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z = </span>\frac{45}{5}

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Question 2:

<span>5(2z + 4) = 0
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10z + 20 = 0

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z = -2

Hence, the answer is A.

Question 3:

4a + 3(a + 1) = 24

4a + 3a + 3 = 24

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a = </span>\frac{21}{7}

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Question 4:

<span>3(4x + 5) = 12

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Question 5:

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8 0
3 years ago
Read 2 more answers
Suppose that 4 fair coins are tossed. Let Equals The event that exactly 2 coins show tails and Equal The event that at least 2 c
faust18 [17]

Answer:

a) P ( E | F ) = 0.54545

b) P ( E | F' ) = 0

Step-by-step explanation:

Given:

- 4 Coins are tossed

- Event E exactly 2 coins shows tail

- Event F at-least two coins show tail

Find:

- Find P ( E |  F )

- Find P ( E | F prime )

Solution:

- The probability of head H and tail T = 0.5, and all events are independent

So,

                    P ( Exactly 2 T ) = ( TTHH ) + ( THHT ) + ( THTH ) + ( HTTH ) + ( HHTT) + ( HTHT)  = 6*(1/2)^4 = 0.375

                    P ( At-least 2 T ) = P ( Exactly 2 T ) + P ( Exactly 3 T ) + P ( Exactly 4 T) = 0.375 + ( HTTT) + (THTT) + (TTHT) + (TTTH) + ( TTTT)

      = 0.375 + 5*(1/2)^4 = 0.375 + 0.3125 = 0.6875

- The probabilities for each events are:

                    P ( E ) = 0.375

                    P ( F ) = 0.6875

- The Probability to get exactly two tails given that at-least 2 tails were achieved:

                    P ( E | F ) = P ( E & F ) / P ( F )

                    P ( E | F ) = 0.375 / 0.6875

                    P ( E | F ) = 0.54545

- The Probability to get exactly two tails given that less than 2 tails were achieved:

                    P ( E | F' ) = P ( E & F' ) / P ( F )

                    P ( E | F' ) = 0 / 0.6875

                    P ( E | F' ) = 0                

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The answer is letter C, which is (2,1)
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