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jasenka [17]
3 years ago
6

Express

Mathematics
1 answer:
krok68 [10]3 years ago
4 0

Answer:

\frac{15}{9}  (7 + 2 \sqrt{10} )

Step-by-step explanation:

The solution is in the picture

At line 7, the denominator of the expression contains irrational number (which is surd 10). This shows that the expression is not simplified

At line 8 of my solution, multiply both numerator and denominator by the conjugate of

7 - 2 \sqrt{10}

which is

7 + 2 \sqrt{10}

in order to eliminate irrational number at denominator

More info of conjugate

The conjugate of a+b is a-b,

Why conjugate? Try it yourself!

Hint: (a+b)(a-b) = a^2 - b^2

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What is the graph of the function f(x) = the quantity of negative x squared minus 2 x minus 2, all over x minus 2
Serjik [45]

Answer:

use desmos and type in the equation to get the graph

Step-by-step explanation:

5 0
3 years ago
A coffee shop orders at most $3,500 worth of coffee and tea. The shop needs to make a profit of at least $1,900 on the order. Th
o-na [289]

Answer:

Which graph's shaded region represents the possible combinations of coffee and tea for this order?


3 0
3 years ago
Read 2 more answers
Write the STANDARD FORM of the equation through the point (4,-4) witha slope of -2.
boyakko [2]

The general equation of line with the slope "m" and passing points (a,b) is :

y - b = m (x -a)

In the given question:

Slope m = -2, passing points (a,b) = (4,-4)

Substitute the value of a = 4, b = -4 in the general equation of line

\begin{gathered} y-b=m(x-a) \\ y-(-4)=(-2)(x-4) \\ y+4=-2(x-4) \\ y+4=-2x+8 \\ y+2x=8-4 \\ 2x+y=4 \end{gathered}

The equation with the slope -2 and passing points (4,-4) is 2x + y = 4

Answer : 2x + y = 4

8 0
1 year ago
I need help please anyone help please
steposvetlana [31]

Answer:

1.

A. 17h+15=c

B. 4

*Steps*

83-15=68

68/17=4

2(box 1):

how to solve: 25m+200=?

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8 0
3 years ago
Find the area of each sector shown (the shaded section)
mihalych1998 [28]

Answer:

The area of the sector (shaded section) is 29.51 m^{2}.

Step-by-step explanation:

Area of a sector = (θ ÷ 360) \pir^{2}

where θ is the central angle of the sector, and r is the radius of the circle.

From the diagram give, diameter of the circle is 26 m. So that;

r = \frac{diameter}{2}

 = \frac{26}{2} = 13 m

θ = 360 - (180 + 160)

  = 360 - 340

  = 20^{o}

Thus,

area of the given sector = \frac{20}{360} x \frac{22}{7} x (13)^{2}

                                        = \frac{20}{360} x x \frac{22}{7} x 169

                                         = 29.5079

The area of the sector (shaded section) is 29.51 m^{2}.

4 0
3 years ago
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