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3 years ago

A healthy, adult cheetah can run 110 feet per second. How fast can a cheetah run in miles per hour?

Mathematics

2 answers:

ipn [44]3 years ago

7 0

75 miles per hour.
all you have to do it convert the it to the mph

stealth61 [152]3 years ago

7 0

75 miles per hour :)

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Convert the following equation to slope-intercept form:<br> 12x + 12y = 36

Nuetrik [128]

Answer:

Slope = -2.000/2.000 = -1.000

x-intercept = 3/1 = 3.00000

y-intercept = 3/1 = 3.00000

6 0

3 years ago

Read 2 more answers

Find value of the variable

just olya [345]

Answer:

x=10

Step-by-step explanation:

16/24=(x-2)/12

or, 16/2=x-2

or, 8=x-2

or, x-2=8

or, x=10

Answered by GAUTHMATH

7 0

3 years ago

Determine whether the given differential equation is exact. If it is exact, solve it. (If it is not exact, enter NOT.) (tan(x) −

never [62]

Answer:

$f(x,y)=ln secx+cosx siny+C$

Step-by-step explanation:

We are given that DE

$(tanx-sinx siny)dx+cosxcosydy=0$

We have to determine given DE is exact or not.

Compare it with Mdx+Ndy=0

$M=tanx-sinx siny$

$N=cosxcosy$

$\frac{\partial M}{\partial y}=$ $M_y=-sinxcosy$

$\frac{\partial N}{\partial x}=N_x=-sinxcosy$

Therefore, $M_y=N_x$

If DE is exact then $M_y=N_x$

Hence,it is exact.

$M=\frac{\partial f}{\partial x}=tanx-sinxsiny$

Integrate w.r.t x on both sides

$f(x,y)=\int(tanx-sinxsiny)dx$

$f(x,y)=lnsecx+cosxsiny+\phi(y)$ ...(1)

By using the formula

$\int tanxdx=lnsecx+C,\int sinxdx=-cosx+C$

Differentiate partially equation (1) w.r.t y

$\frac{\partial f}{\partial y}=cosxcosy+\phi'(y)$

By using the formula:

$\frac{d(sinx)}{dx}=cosx$

$N=\frac{\partial f}{\partial y}=cosxcosy=cosxcosy+\phi'(y)$

$\phi'(y)=cosxcosy-cosxcosy=0$

$\phi'(y)=0$

Integrate w.r.t y

$\phi(y)=C$

Substitute the value

$f(x,y)=ln secx+cosx siny+C$

7 0

3 years ago

A new school has x day students and y boarding students.

guapka [62]

Given:

The fees for a day student are $600 a term.

The fees for a boarding student are $1200 a term.

The school needs at least $720000 a term.

To show:

That the given information can be written as $x + 2y\geq 1200$ .

Solution:

Let x be the number of day students and y be the number of boarding students.

The fees for a day student are $\$600$ a term.

So, the fees for $x$ day students are $\$600x$ a term.

The fees for a boarding student are $\$1200$ a term.

The fees for $y$ boarding student are $\$1200y$ a term.

Total fees for $x$ day students and $y$ boarding student is:

$\text{Total fees}=600x+1200y$

The school needs at least $720000 a term. It means, total fees must be greater than or equal to $720000.

$600x+1200y\geq 720000$

$600(x+2y)\geq 720000$

Divide both sides by 600.

$\dfrac{600(x+2y)}{600}\geq \dfrac{720000}{600}$

$x+2y\geq 1200$

Hence proved.

3 0

3 years ago

Quadrilateral OPQR: O(1,-5), P(3,-4), Q(7,-3), R (5,-2). Translate this quadrilateral (x,y)----> (x-5,y +7) creating image O'

labwork [276]

Answer:(x,y)⇒(x-5,y+7)

0'⇒(-4,2),

P'(-2,3)

Q'(2,4)

R'(0,5)

(x,y)⇒(-x,-y)

O'((1,-5)⇒O''(-1,5)

P'(-2,3)⇒P''(2,-3)

Q'(2,4)⇒Q''(-2,-4)

R'(0,5)⇒R''(0,-5)

Step-by-step explanation:

3 0

3 years ago