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SCORPION-xisa [38]
3 years ago
12

2(3x-4)=3x+1 what is x?

Mathematics
2 answers:
Flura [38]3 years ago
8 0
2(3x-4)=3x+1
6x-8=3x+1
6x+3x=1+8
3x=9
x=3
pogonyaev3 years ago
5 0
<span><span>2<span>(<span><span>3x</span>−4</span>)</span></span>=<span><span>3x</span>+1

</span></span>Step 1: Simplify both sides of the equation.

<span><span>2<span>(<span><span>3x</span>−4</span>)</span></span>=<span><span>3x</span>+1</span></span><span>Simplify: (Show steps)</span><span><span><span>6x</span>−8</span>=<span><span>3x</span>+1

</span></span>Step 2: Subtract 3x from both sides.

<span><span><span><span>6x</span>−8</span>−<span>3x</span></span>=<span><span><span>3x</span>+1</span>−<span>3x</span></span></span><span><span><span>3x</span>−8</span>=1

</span>Step 3: Add 8 to both sides.

<span><span><span><span>3x</span>−8</span>+8</span>=<span>1+8</span></span><span><span>3x</span>=9

</span>Step 4: Divide both sides by 3.

<span><span><span>3x</span>3</span>=<span>93

</span></span><span> answer : x=<span>3

hope this helps!</span></span>
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Given that α and β are the roots of the quadratic equation <img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B6x-7%3Dp" id="Tex
siniylev [52]

Answer:

\large \boxed{\sf \ \ \ p=-11 \ \ \ }

Step-by-step explanation:

Hello,

\alpha \text{ and } \beta \text{ are the roots of the following equation}

   2x^2+6x-7=p

It means that

   2\alpha^2+6\alpha-7=p \\\\2\beta ^2+6\beta -7=p \\\\

And we know that

\alpha= 2\cdot \beta

So we got two equations

   2(2\beta)^2+6\cdot 2 \cdot \beta -7=p \\\\8\beta^2+12\beta -7=p\\\\ and \ 2\beta ^2+6\beta -7=p \ So \\\\\\8\beta^2+12\beta -7 = 2\beta ^2+6\beta -7\\\\6\beta^2+6\beta =0\\\\\beta(\beta+1)=0\\\\ \beta =0 \ or \ \beta=-1

For \beta =0, \ \ \alpha =0, \ \ p = -7

For \beta =-1, \ \ \alpha =-2, \ \ p= 2-6-7=-11, \ p=2*4-12-7=-11

I assume that we are after two different roots so the solution for p is p=-11

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x(x-1)=x^2-x

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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