Answer: The length of the other leg is 20 cm.
Step-by-step explanation: As shown in the attached figure, triangle ABC is a right-angled triangle, where
m∠B = 90°, hypotenuse, AC = 25 cm and shorter leg, AB = 15 cm.
We are to find the length of the other leg, BC.
From Pythagoras theorem, we have
![AC^2=AB^2+BC^2\\\\\Rightarrow BC^2=\sqrt{AC^2-AB^2}\\\\\Rightarrow BC=\sqrt{25^2-15^2}\\\\\Rightarrow BC=\sqrt{625-225}\\\\\Rightarrow BC=\sqrt{400}\\\\\Rightarrow BC=20.](https://tex.z-dn.net/?f=AC%5E2%3DAB%5E2%2BBC%5E2%5C%5C%5C%5C%5CRightarrow%20BC%5E2%3D%5Csqrt%7BAC%5E2-AB%5E2%7D%5C%5C%5C%5C%5CRightarrow%20BC%3D%5Csqrt%7B25%5E2-15%5E2%7D%5C%5C%5C%5C%5CRightarrow%20BC%3D%5Csqrt%7B625-225%7D%5C%5C%5C%5C%5CRightarrow%20BC%3D%5Csqrt%7B400%7D%5C%5C%5C%5C%5CRightarrow%20BC%3D20.)
Thus, the length of the other leg is 20 cm.