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3 years ago

I need help, an answer or how to- will be fine, thank you. (i’ll mark brainliest if i can)

Mathematics

1 answer:

siniylev [52]3 years ago

7 0

by solving the first equation you'll get x= -24/13

if you solve the second option (B) then you'll the same result i.e x=-24/13

so option C is correct

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. On a school field trip, the school requires that there are 6 teachers for every 90 students. If 135 students attend the trip h

mr_godi [17]

Answer:

For 135 students , the number of teacher requires is 9

Step-by-step explanation:

Given as :

The number of teacher = 6

The number of student = 90

∵ For 90 students , the number of teacher requires = 6

So , For 1 student , the number of teacher requires = $\frac{6}{90}$

= $\frac{1}{15}$

∴ For 135 student , the number of teacher requires = $\frac{1}{15}$ ×135

Or, For 135 student , the number of teacher requires = $\frac{135}{15}$

So, For 135 student , the number of teacher requires = 9

Hence For 135 students , the number of teacher requires is 9 Answer

5 0

3 years ago

The number of positive resl rootd for the expression for -3x³+8x²-7x+10=0 is less than or equal to

Damm [24]

Step-by-step explanation:

By Descartes' Rule of Signs, f(x) = -3x³ + 8x² - 7x + 10 changes sign 3 times, so there are 1 or 3 positive roots.

5 0

3 years ago

Wich proportion would you set up to change 5 pounds to ounces

Gnesinka [82]

Answer:

80 oz

Step-by-step explanation:

There are 16 ounces in a pound, so:

5 lbs (16 oz/1 lbs)

Multiply the 2 and you get 80 oz.

6 0

3 years ago

Read 2 more answers

What is the value of the 4 in 3.954

antiseptic1488 [7]

Answer:

The value is ones lol thats easy mark me brainliest plzzz

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

A student is studying a population of 100 Daylilies by the roadside. The plants in this population are genetically variable. The

Murljashka [212]

Answer:

broad sense heritability = 0.75

Step-by-step explanation:

Step 1: Variables

phenotypic variation (Vp)

genotype variation (Vg)

environment variation (Ve)

broad sense heritability (H)

Step 2: Formulas:

H = Vg / Vp

Vp = Vg + Ve

Vg = Vp - Ve

Step 3: Given data

Vp = 20

Ve = 5

Step 4: Computation

Vg = 20 - 5 = 15

H = 15 / 20

H = 0.75

Hope this helps!

5 0

3 years ago