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solmaris [256]
3 years ago
5

What is the remainder of (2x3 − 18x + 5) ÷ (x − 3)?

Mathematics
1 answer:
Hatshy [7]3 years ago
8 0
I may be incorrect so verify with someone
(2×3-18x+5) ÷(x-3)
(6-18x +5) ÷ (x-3)
11-18x ÷x-3

the last part is in the image

GOOD LUCK
PLEASE GIVE ME BRAINLIEST BECAUSE THIS WAS KINDA HARD

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Help me plz. Haven’t been able to answer this problem. Even my TEACHER is stumped. (Mark brainliest)
vazorg [7]

Answer:

K 48 inches

Step-by-step explanation:

First lets determine how big of table cloth we need

The table is 3 ft in diameter which is 36 inches

That means the radius is d/2 = 36/2 = 18 inches

We need to add 5 inches to the radius to hang over the edge

18+5 = 23

We need to add the hem which is 1 inch

23+1 = 24

The radius is 24 inches

The diameter would be 2r = 2*24 = 48 inches

3 0
3 years ago
Read 2 more answers
X squared minus 3x minus 4 equals 0
QveST [7]

Answer: What am I solving for?

Step-by-step explanation: ?

7 0
3 years ago
Give the equation of the line through the point ( - 10,9) with a slope of -1/5
hichkok12 [17]

Equation of the line in slope-intercept form is y = -1/5 x + 9

Step-by-step explanation:

  • Step 1: Given slope of the line is -1/5 and the point is (-10, 9). Here m=-1/5.

⇒ y = -1/5 x + b  ------ (1)

  • Step 2: Find the y-intercept of the line, b. Since the line passes through (-10, 9) substitute x = -10 and y = 9 in eq(1)

⇒ 9 = -1/5 × -10 + b = 2 + b

⇒ b = 9 - 2 = 7

  • Step 3: Slope intercept form of the line is y = mx + b. Form the equation using the values of m and b.

⇒ y = -1/5 x + 7

It can also be written as 5y + x = 35

7 0
3 years ago
What is the coefficient of the x^5y^5- term in the biomial expansion of (2x-3y)^10
jasenka [17]

<u>Answer:</u>

 The coefficient of x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552

<u>Solution: </u>

The given expression is (2 x-3 y)^{10}

As per binomial theorem, we know,

(x+y)^{n}=\sum n C_{k} x^{n-k} y^{k}

Now here a = 2x, b = (- 3y) and n = 10 and k = 0,1,2,….10

Now x^{5}\times y^5 will be the 6 term where k =5

Now, \mathrm{T}_{6}=10 \mathrm{C}_{5} \times(2 \mathrm{x})^{(10-5)} \times(-3 \mathrm{y})^{5}=10 \mathrm{C}_{5} 2^{5} \times \mathrm{x}^{5} \times(-3)^{5} \times \mathrm{y}^{5}

So, the coefficient of x^{5} \times y^{5} \text { is }=10\left(5 \times 2^{5} \times(-3)^{5}\right.

10 \mathrm{C}_{5}=\frac{10 !}{5 ! \times(10-5) !}=\frac{10 !}{5 !+5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6 \times 5 !}{5 ! \times 5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2 \times 1}=\left(\frac{30240}{120}\right)=252

The coefficient of x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552

6 0
3 years ago
I need help with this can you please help me?
Vikki [24]
2. 12x5y
 3.7.402 x 10^6
4. 2.36 x 10^2, 2.36 x 10^3, 23.6 x 10^3
4 0
3 years ago
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