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2 years ago

Lynn says that the product of 4/5 and 5/2 is greater than 4/5.Which statement is true?

Mathematics

2 answers:

Alexus [3.1K]2 years ago

7 0

Answer:5/2 is greater I believe

Step-by-step explanation:

Nataly_w [17]2 years ago

3 0

Answer:

Lynn was correct because multiplicative factor 5/2 is greater than 1 or the the product is 2 which is greater than 4/5.

Step-by-step explanation:

Lynn says that the product of 4/5 and 5/2 is greater than 4/5.

We know that if numerator is less that the denominator, then the value of fraction is less than 1.

$\dfrac{4}{5}$

$\dfrac{5}{2}>1$

Product of 4/5 and 5/2 is

$\dfrac{4}{5}\times \dfrac{5}{2}=2$

2 is greater than 4/5. So, Lynn was correct.

If a positive number multiplied by a factor greater than 1, then the product will be larger than the original number.

In the given problem, original number is 4/5 and the multiplicative factor is 5/2.

Lynn was correct because multiplicative factor 5/2 is greater than 1.

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Suppose that an airline uses a seat width of 16.5 in. Assume men have hip breadths that are normally distributed with a mean of

Alexxx [7]

Answer:

a) 0.018

b) 0

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 14.4 in

Standard Deviation, σ = 1 in

We are given that the distribution of breadths is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(breadth will be greater than 16.5 in)

P(x > 16.5)

$P( x > 16.5) = P( z > \displaystyle\frac{16.5 - 14.4}{1}) = P(z > 2.1)$

$= 1 - P(z \leq 2.1)$

Calculation the value from standard normal z table, we have,

$P(x > 16.5) = 1 - 0.982 = 0.018 = 1.8\%$

0.018 is the probability that if an individual man is randomly selected, his hip breadth will be greater than 16.5 in.

b) P( with 123 randomly selected men, these men have a mean hip breadth greater than 16.5 in)

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

P(x > 16.5)

$P( x > 16.5) = P( z > \displaystyle\frac{16.5-14.4}{\frac{1}{\sqrt{123}}}) = P(z > 23.29)$

$= 1 - P(z \leq 23.29)$

Calculation the value from standard normal z table, we have,

$P(x > 16.5) = 1 - 1 = 0$

There is 0 probability that 123 randomly selected men have a mean hip breadth greater than 16.5 in

4 0

3 years ago

3 thousands divided by 10

aleksandrvk [35]

3 thousands devided by 10= 3 hundreds= (300)

7 0

3 years ago

Read 2 more answers

A small ball floats on the surface of the water in a wave pool. As a wave moves past the ball, the ball's

stiks02 [169]

Answer:

The correct option is;

d(t) = 6·cos(π/3·t) + 28

Step-by-step explanation:

The general form of a cosine function is given as follows;

y = A·cos(B·x - C) + D

Where;

A = The amplitude = The distance from the peak to the midline = 1/2×(Maximum - minimum)

The amplitude = 1/2 × (34 - 22) = 6 inches

B = 2·π/P = 2·π/6 = π/3

P = The period = 6 seconds

C/B = The phase shift

D = The midline = Minimum + Amplitude = 22 + 6 = 28 inches

x = The independent variable

Therefore, to model the function of the wave can be given as follows;

d(t) = 6·cos(π/3·t) + 28

6 0

2 years ago

A wind turbine is located at the top of a hill where the wind blows steadily at 12 m/s, and stands 37 m tall. The air then exits

marta [7]

Answer:

Power generated = 4.315 kW

Step-by-step explanation:

Given,

speed of wind when enters into the turbine, V = 12 m/s

speed of wind when exits from the turbine, U = 9 m/s

mass flow rate of the wind, m = 137 kg/s

According to the law of conservation of energy

Energy generated = change in kinetic energy

Since, the air is exiting at same elevation. So, we will consider only kinetic energy.

Energy generated in one second will be given by,

$E\ =\ \dfrac{1}{2}.mV^2-\dfrac{1}{2}.m.U^2$

$=\ \dfrac{1}{2}\times 137\times (12)^2-\dfrac{1}{2}\times 137\times (9)^2$

=4315.5 J

= 4.315 kJ

So, energy is generated in one second = 4.315 kJ

Power generated can be given by,

$P\ =\ \dfrac{\textrm{energy generated}}{time}$

And the energy is generated is already in per second so power generated will be 4.315 kW.

8 0

3 years ago

(20 points) Please answer and explain!

liq [111]

Answer:

$\large\boxed{a.\ -3x^5y^6}$

Step-by-step explanation:

$-3x^2y^2\cdot y^4x^3=(-3)(x^2x^3)(y^2y^4)\\\\\text{use}\ a^na^m=a^{n+m}\\\\=-3x^{2+3}y^{2+4}=-3x^5y^6$

3 0

3 years ago