Air energy
Heat energy
Kinetic energy
:-)
Answer:
The 99% confidence interval is between 62.36%(lower bound) and 89.64%(upper bound).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
![\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}](https://tex.z-dn.net/?f=%5Cpi%20%5Cpm%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D)
In which
z is the zscore that has a pvalue of
.
A sample of 65 students from the freshmen class is used and a mean score of 76% correct is obtained.
This means that ![n = 65, \pi = 0.76](https://tex.z-dn.net/?f=n%20%3D%2065%2C%20%5Cpi%20%3D%200.76)
99% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
![\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.76 - 2.575\sqrt{\frac{0.76*0.24}{65}} = 0.6236](https://tex.z-dn.net/?f=%5Cpi%20-%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D%20%3D%200.76%20-%202.575%5Csqrt%7B%5Cfrac%7B0.76%2A0.24%7D%7B65%7D%7D%20%3D%200.6236)
The upper limit of this interval is:
![\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.76 + 2.575\sqrt{\frac{0.76*0.24}{65}} = 0.8964](https://tex.z-dn.net/?f=%5Cpi%20%2B%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D%20%3D%200.76%20%2B%202.575%5Csqrt%7B%5Cfrac%7B0.76%2A0.24%7D%7B65%7D%7D%20%3D%200.8964)
0.6236*100 = 62.36%
0.8964*100 = 89.64%
The 99% confidence interval is between 62.36%(lower bound) and 89.64%(upper bound).
Answer:
12
Step-by-step explanation:
2x + 24° = 4x ( being vertically opposite angles)
4x - 2x = 24°
2x = 24°
x = 24° / 2
x = 12°
Hope it will help :)
I am pretty sure it is 0.064. Hope this helps
Answer:
0.173 probability that she gets exactly three questions correct.
Step-by-step explanation:
For each question, there are only two possible outcomes. Either she guesses the correct answer, or she does not. The probability of guessing the correct answer for a question is independent of other questions. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.
![C_{n,x} = \frac{n!}{x!(n-x)!}](https://tex.z-dn.net/?f=C_%7Bn%2Cx%7D%20%3D%20%5Cfrac%7Bn%21%7D%7Bx%21%28n-x%29%21%7D)
And p is the probability of X happening.
Seven questions:
This means that ![n = 7](https://tex.z-dn.net/?f=n%20%3D%207)
Each question has four choices.
Abby guesses, which means that ![p = \frac{1}[4} = 0.25](https://tex.z-dn.net/?f=p%20%3D%20%5Cfrac%7B1%7D%5B4%7D%20%3D%200.25)
Find the probability to the nearest thousandth, that Abby gets exactly three questions correct.
This is P(X = 3).
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
![P(X = 3) = C_{7,3}.(0.25)^{3}.(0.75)^{4} = 0.173](https://tex.z-dn.net/?f=P%28X%20%3D%203%29%20%3D%20C_%7B7%2C3%7D.%280.25%29%5E%7B3%7D.%280.75%29%5E%7B4%7D%20%3D%200.173)