Answer : option B
Given: center (4,2), vertex (9,2), and focus (4+2sqrt5,2)
The distance between vertex and center is 9-4 = 5
Center is (h,k) so h= 4 and k =2
focus is (h+c,k)
From the given focus (4+2sqrt5,2), c= 2sqrt(5)
Standard form of equation is

h= 4, k=2, a=5, c=2sqrt(5), we need to find out b




b^2 = 5
plug in all the values


Option B is correct
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Answer:
10w+8
Step-by-step explanation:
-10(-w)+8
10w+8

Actually Welcome to the Concept of the Differential Calculus.
Since, we know this is a definite calculus,
thus we get here as, by using the Chain Rule.
Answer:
13
Step-by-step explanation: