Evaluate the expression 4-2x2+3

Las edades de dos hermanos tienen una razón de 2 a 1. Cuando transcurran 4 años, la razón entre sus edades será de 8 a 6. ¿Cuánt

Nataly [62]

Answer:

The age of brothers are 4 years and 2 years respectively.

Step-by-step explanation:

We are given that the ages of two brothers have a ratio of 2 to 1. When 4 years have passed, the ratio of their ages will be 8 to 6.

Let the age of the first brother be 'x years' and the age of the second brother be 'y years'.

So, according to the question;

The first condition states that the ages of two brothers have a ratio of 2 to 1, that means;

$\frac{x}{y} =\frac{2}{1}$

$x=2y$ -------------- [equation 1]

The second condition states that when 4 years have passed, the ratio of their ages will be 8 to 6, that means;

$\frac{x+4}{y+4}=\frac{8}{6}$

$6({x+4})=8}(y+4)$

$6x+24=8y+32$

$6(2y)+24=8y+32$

$12y-8y=32-24$

$4y=8$

$y=\frac{8}{4}$ = 2 years

Putting the value of y in equation 1 we get;

x = 2y

x = $2 \times 2$ = 4 years

Hence, the age of brothers are 4 years and 2 years respectively.

3 0

3 years ago

The quality-control manager of a large factory is concerned about the number of defective items produced by workers. Thirty work

kotegsom [21]

Answer:

a. There is no blocking variable, and incentive plans will be randomly assigned to the workers.

Step-by-step explanation:

The Randomized Complete Block Design (RCBD) is a standard experimental design where experimental units or subjects are grouped as blocks (also known as replicates). In RCBD, subjects within each block are randomly assigned to the experimental units within a block. RCBD is a type of design that reduces variability by controlling variation within each treatment, thereby enhancing the estimation of the treatment effects (combinations of the factor levels of the different factors).

6 0

3 years ago

Please explain how to get the answer.

Maru [420]

2r=R

Because 2 of "r" make 1 R

3 0

3 years ago

Read 2 more answers

What is the quotient in simplified form? State any restrictions on the variable? \frac{x^2-16}{x^2+5x+6} /\frac{x^2+5x+4}{x^2-2x

lora16 [44]

$\frac{x^2-16}{x^2+5x+6} / \frac{x^2+5x+4}{x^2-2x-8}$

We can begin by rearranging this into multiplication:

$\frac{x^2-16}{x^2+5x+6} * \frac{x^2-2x-8}{x^2+5x+4}$

Now we can factor the numerators and denominators:

$\frac{(x+4)(x-4)}{(x+3)(x+2)} * \frac{(x-4)(x+2)}{(x+4)(x+1)}$

The factors (x+4) and (x+2) cancel out, leaving us with:

$\frac{(x-4)}{(x+3)} * \frac{(x-4)}{(x+1)}$

Our answer comes out to be:

$\frac{(x-4)^{2} }{(x+3)(x+1)}$ or $\frac{ x^{2} -8x+16}{ x^{2}+4x+3 }$

Based on the numerator of the second fraction (since we used its inverse), the denominators of both, and the factors we canceled out earlier, the restrictions are x ≠ -4, -3, -2, -1, 4

4 0

3 years ago

I need help on these 2 questions. Algebra 1

hammer [34]

Answer:

7. is G

8. f(4)=-120

Step-by-step explanation:

7. les do f(0)=4 since its the easiest

F. f(0)=0.4(0+5)(0-2)

0.4*-2*5=-4 NOT IT. the ans. is +

G. f(0)=-0.4(0+5)(0-2)

-0.4*-2*5=4 YESSSSSS

H. f(0)=-0.4(0-5)(0+2)

-0.4*2*-5=4 YESSSSSS

J. f(0)=0.4(0-5)(0+2)

0.4*2*-5=-4 NOT ITTTT

so G n H

Put both equation=0

G. 0=-0.4(x+5)(x-2)

x=-5,2 YASSSS this is the ans.

4 0

3 years ago