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kupik [55]
3 years ago
7

Help me please if you know

Mathematics
2 answers:
11111nata11111 [884]3 years ago
6 0

The picture is blurry and I can't read this

blagie [28]3 years ago
3 0

This Image is blurry, and I am unable to read it. If you still would like some help, please repost your question and I'm sure people would love to answer your question. Have a nice day :)

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Round 50.341 to the nearest hundredth.<br><br><br><br><br> Can someone plz help me
Alborosie

Answer:

50.04

Step-by-step explanation:

hope it helps you

please mark me as brainliest

5 0
2 years ago
Prove that: [1 + 1/tan²theta] [1 + 1/cot² thata] = 1/(sin²theta - sin⁴theta]
Stels [109]

Step-by-step explanation:

<h3><u>Given :-</u></h3>

[1+(1/Tan²θ)] + [ 1+(1/Cot²θ)]

<h3><u>Required To Prove :-</u></h3>

[1+(1/Tan²θ)]+[1+(1/Cot²θ)] = 1/(Sin²θ-Sin⁴θ)

<h3><u>Proof :-</u></h3>

On taking LHS

[1+(1/Tan²θ)] + [ 1+(1/Cot²θ)]

We know that

Tan θ = 1/ Cot θ

and

Cot θ = 1/Tan θ

=> (1+Cot²θ)(1+Tan²θ)

=> (Cosec² θ) (Sec²θ)

Since Cosec²θ - Cot²θ = 1 and

Sec²θ - Tan²θ = 1

=> (1/Sin² θ)(1/Cos² θ)

Since , Cosec θ = 1/Sinθ

and Sec θ = 1/Cosθ

=> 1/(Sin²θ Cos²θ)

We know that Sin²θ+Cos²θ = 1

=> 1/[(Sin²θ)(1-Sin²θ)]

=> 1/(Sin²θ-Sin²θ Sin²θ)

=> 1/(Sin²θ - Sin⁴θ)

=> RHS

=> LHS = RHS

<u>Hence, Proved.</u>

<h3><u>Answer:-</u></h3>

[1+(1/Tan²θ)]+[1+(1/Cot²θ)] = 1/(Sin²θ-Sin⁴θ)

<h3><u>Used formulae:-</u></h3>

→ Tan θ = 1/ Cot θ

→ Cot θ = 1/Tan θ

→ Cosec θ = 1/Sinθ

→ Sec θ = 1/Cosθ

<h3><u>Used Identities :-</u></h3>

→ Cosec²θ - Cot²θ = 1

→ Sec²θ - Tan²θ = 1

→ Sin²θ+Cos²θ = 1

Hope this helps!!

7 0
2 years ago
To clear both of the fractions from fox + 7 = 5 – x, we can multiply both sides of
tatyana61 [14]

Answer:

6,10,or 30 is your answer

3 0
3 years ago
When a constant force is applied to an object, the acceleration of the object varies inversely with its mass. When a certain con
maria [59]

First:

F=m.a

=4*7

=28N

Second:

F=m.a

28=m.2. (force is constant,so F=28N)

28/2=m

m=14kg.

5 0
3 years ago
Read 2 more answers
Ryan runs 1.5 miles on his first day of training for a road race. The next day he increases his distance run by 0.3 miles. The d
SVEN [57.7K]

Answer:

sorry I need points

Step-by-step explanation:

so so sorry

8 0
2 years ago
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