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4 years ago

Element “X” is a brand new element. Scientists discovered that 80% of the atoms of element

Chemistry

1 answer:

alexandr1967 [171]4 years ago

6 0

Answer:

Average atomic mass of X is 10.2 amu.

Explanation:

Given data:

Percentage abundance of X-10 = 80%

Percentage abundance of X-11 = 20%

Average atomic mass of X = ?

Solution:

Average atomic mass of X = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100

Average atomic mass of \X = (80×10)+(20×11) /100

Average atomic mass of X = 800 + 220 / 100

Average atomic mass of \X = 1020 / 100

Average atomic mass of X = 10.2 amu

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Calculate a reasonable amount (mass in g) of your unknown acid to use for a titration. You will want about 30 mL of titrant to g

Vinil7 [7]

Answer:

"0.60 g" is the appropriate solution.

Explanation:

The given values are:

Volume of base,

= 30 ml

Molarity of base,

= 0.05 m

Molar mass of acid,

= 400 g/mol

As we know,

⇒ $Molarity=\frac{Number \ of \ moles \ of \ base}{Number \ of \ solution}$

On substituting the values, we get

⇒ $0.05=\frac{Number \ of \ moles \ of \ base}{30\times 10^{-3}}$

⇒ $Number \ of \ moles \ of \ base=0.05\times 30\times 10^{-3}$

⇒ $=1.5\times 10^{-3}$

hence,

⇒ $Moles \ of \ acid=\frac{Mass \ of \ acid}{Molar \ mass \ of \ acid}$

On substituting the values, we get

⇒ $1.5\times 10^{-3}=\frac{Mass \ of \ acid}{400}$

⇒ $Mass \ of \ acid=1.5\times 10^{-3}\times 400$

⇒ $=0.60 \ g$

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Marina86 [1]

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grigory [225]

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