Answer:
B. Convert mass percents to moles and then divide by the smallest mole value to get subscripts
Explanation:
The empirical formula is the smallest whole number ratio the elements in a compound can possess. According to this question, to derive the empirical formula of a compound from its percent composition of elements that make it up, the following steps are followed:
- First, since the elements are in percentage, one would assume the total mass of the compound is 100g and take each percentage as the mass of each element. For example, if a compound contains 16% oxygen, it means that 16g of oxygen is present.
- Next, we convert the mass of each element to moles by dividing the mass value by the molar mass of each element. For example, 16g of oxygen will be 16g/16g/mol = 1mol
- Next, we divide each mole value by the smallest mole value to get the subscript of each element that will be used in the empirical formula.
[Co(CN)₆]³⁻ → Yellow
[Co(NH₃)₆]³⁺ → Orange
[CoF₆]³⁻ → Blue
Explanation:
- All the given compounds have octahedral geometry but the ligand in each are different with the same metal ion.
- Ligands strength order: CN⁻ > NH₃ > F⁻
- The ligand CN will act as a strong field ligand so that the splitting is maximum when compared to NH₃ and F⁻
- If the splitting is more, the energy required for transition is more, and the wavelength is inversely proportional to energy.
- So CN complex will absorb at lower wavelength (yellow color)
Answer: Rotation occurs at single bonds that are sigma bonds. Rotational barrier is the amount of activation energy required to covert rotamer to another by rotation that occurs around the sigma bond(C-C single bond). Due to the presence of steric hindrance that is the nonbonding interaction effects the reactivity of ions and molecules, activation energy increases. So the rotational barrier in butenyl cation is high.
<span> la gravedad en la tierra no es constante ni mucho menos porque depende de la distancia al centro de la tierra... y la tierra no es perfectamente esferica </span>
<span>respecto a la pregunta, la presion atmosferica viene siendo proporcional al peso que el aire ejerce sobre nosotros. Mientras mas gravedad hay en un planeta, mayor es la presion atmosferica a cierta altura. </span>
<span>Ahora, en un mismo planeta, la aceleracion de gravedad disminuye con la altura (porque se esta mas lejos del centro) y la presion tambien disminuye con la altura, porque hay menos aire sobre nuestras cabezas. </span>
<span>espero q te sirva.</span>
